CInt in VB.net

Hi,

I have a question regarding the use of CInt and/or Char
member functions.

Let's say I have an input string,

Dim input As String = "7.5"

and I need to check if this string(number) is either 7 or
8 (or so on....), I use the CInt function and compare the
value using If-statement.

"7.5" is supposed to return false to me but CInt now
turns it into 8 (so it returns true now)

Any ideas to fix that?

thanks.

 

CInt will convert to Interger
CDouble will help you.
C???? are leftover of old VB 6, try to get away from it

In .Net it is better to use CType like

if CType(input, double) ....

Good luck
Marc M
MCSD (6.0 & .NET)

 

CInt will convert to Integer
Use CDouble.
All C????? are old VB 6.0 syntax

In .Net use CType to convert like

If CType(input, Double) .......

Hope this helps

Marc M
MCSD (6.0 & .NET)

 

Best way (I think) use .Net System.Convert.ToDouble or
System.Convert.ToDecimal with try & catch. If convert
successful then it is number else it is not.

Example

Public Function SomeFunct(ByVal s As String) As Double
Dim x As Double

' lets say s = "7.1"
Try
x = System.Convert.ToDouble(s)
Return x;
Catch ex As Exception
Return -1 'set -1 to inform you that not number!
End Try

End Function

Hope that helpful.