# Ex 7.6, 11 - Chapter 7 Class 12 Integrals (Term 2)

Last updated at July 11, 2018 by Teachoo

Last updated at July 11, 2018 by Teachoo

Transcript

Ex 7.6, 11 𝑥 cos−1𝑥 1 − 𝑥2 Let cos−1𝑥=𝑡 Differentiating both sides 𝑤.𝑟.𝑡.𝑥 −1 1 − 𝑥2 = 𝑑𝑡𝑑𝑥 𝑑𝑥=− 1 − 𝑥2 𝑑𝑡 Putting the value of cos−1x = t and dx = − 1− x2 dt , we get 𝑥 cos−1𝑥 1 − 𝑥2 .𝑑𝑥 = 𝑥 . 𝑡 1 − 𝑥2 .𝑑𝑥 = 𝑥 . 𝑡 1 − 𝑥2 . − 1 − 𝑥2𝑑𝑡 = −𝑥𝑡 . 𝑑𝑡 = − 𝑥𝑡 . 𝑑𝑡 = − cos𝑡𝑡 . 𝑑𝑡 = − 𝑡 cos𝑡. 𝑑𝑡 =− 𝑡 cos𝑡. 𝑑𝑡− 𝑑𝑡𝑑𝑡 cos𝑡. 𝑑𝑡𝑑𝑡 =− 𝑡 sin𝑡− 1 . sin𝑡𝑑𝑡 =− 𝑡 sin𝑡− − cos𝑡+𝐶 =− 𝑡 sin𝑡+ cos𝑡+𝐶 =−𝑡 sin𝑡− cos𝑡+𝐶 =−𝑡 1− 𝑐𝑜𝑠2𝑡 −𝑐𝑜𝑠𝑡+𝐶 = − cos−1𝑥 1− 𝑥2−𝑥+𝐶 = − 1− 𝑥2 cos−1𝑥+𝑥+𝐶

Ex 7.6

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Ex 7.6, 11 You are here

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Ex 7.6, 23 (MCQ)

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Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.