Another MCSD 70-310 Creating and Consuming .NET Remoting Objects Exam Question

Now here is another question...



You are creating a .NET Remoting application. You use the following code to create and register an HttpServerChannel object to listen at port 8080.



Dim channel as New HttpServerChannel(8080)

ChannelServices.RegisterChannel(SrvrChannel)



However, when you run the application, an exception is thrown. Which of the following reasons explains the exception? (Choose the one correct option.)



A. No ports are available for registering a channel.

B. Another channel with the same name exists in the application domain.

C. You have another HttpServerChannel in the application domain.

D. You have specified a valid name for the HttpServerChannel.

It said that D was wrong, but I couldn't find any information in MSDN on what could be the correct answer.

Make it idiot proof and someone will make a better idiot.

 

I would say the answer is B. In the example given an HTTP channel is being created with no name specified, so the default name is "http". If another HTTP channel had been created first without specifying a name then you would already have a channel named "http" in the AppDomain.

Check out this entry from the .NET 1.1 SDK documentation:

ms-help://MS.NETFrameworkSDKv1.1/cpref/html/frlrfSystemRuntimeRemotingChannelsChannelServicesClassRegisterChannelTopic.htm

"You cannot register two channels with the same name in an AppDomain. By default, the name of an HttpChannel is "http", and the name of a TcpChannel is "tcp". Therefore, if you want to register two channels of the same type, you must specify a different name for one of them through configuration properties."

--
_______________________________
Sam Santiago

Now here is another question...



You are creating a .NET Remoting application. You use the following code to create and register an HttpServerChannel object to listen at port 8080.



Dim channel as New HttpServerChannel(8080)

ChannelServices.RegisterChannel(SrvrChannel)



However, when you run the application, an exception is thrown. Which of the following reasons explains the exception? (Choose the one correct option.)



A. No ports are available for registering a channel.

B. Another channel with the same name exists in the application domain.

C. You have another HttpServerChannel in the application domain.

D. You have specified a valid name for the HttpServerChannel.

It said that D was wrong, but I couldn't find any information in MSDN on what could be the correct answer.

Make it idiot proof and someone will make a better idiot.

 

Bad Gateway
I would say the answer is B. In the example given an HTTP channel is being created with no name specified, so the default name is "http". If another HTTP channel had been created first without specifying a name then you would already have a channel named "http" in the AppDomain.

Check out this entry from the .NET 1.1 SDK documentation:

ms-help://MS.NETFrameworkSDKv1.1/cpref/html/frlrfSystemRuntimeRemotingChannelsChannelServicesClassRegisterChannelTopic.htm

"You cannot register two channels with the same name in an AppDomain. By default, the name of an HttpChannel is "http", and the name of a TcpChannel is "tcp". Therefore, if you want to register two channels of the same type, you must specify a different name for one of them through configuration properties."

--
_______________________________
Sam Santiago

Now here is another question...



You are creating a .NET Remoting application. You use the following code to create and register an HttpServerChannel object to listen at port 8080.



Dim channel as New HttpServerChannel(8080)

ChannelServices.RegisterChannel(SrvrChannel)



However, when you run the application, an exception is thrown. Which of the following reasons explains the exception? (Choose the one correct option.)



A. No ports are available for registering a channel.

B. Another channel with the same name exists in the application domain.

C. You have another HttpServerChannel in the application domain.

D. You have specified a valid name for the HttpServerChannel.

It said that D was wrong, but I couldn't find any information in MSDN on what could be the correct answer.

Make it idiot proof and someone will make a better idiot.

 

Bad Gateway?

You're preparing for the 70-310 and you can't even recognize
a Microsoft Help URN?

I'm surprised you even bother checking the MSDN ...

Maybe somebody else smart enough to use google will benefit
from this in the future.

..NET Framework Class Library
ChannelServices.RegisterChannel Method
http://msdn.microsoft.com/library/d...sChannelServicesClassRegisterChannelTopic.asp

 

Thank you, slave.

being created with no name specified, so the default name is "http". If
another HTTP channel had been created first without specifying a name then
you would already have a channel named "http" in the AppDomain.

By default, the name of an HttpChannel is "http", and the name of a
TcpChannel is "tcp". Therefore, if you want to register two channels of the
same type, you must specify a different name for one of them through
configuration properties."

http://msdn.microsoft.com/library/d...elsChannelServicesClassRegisterChannelTopic.a
sp

 

This person is posting questions from the actual exam, no
doubt obtained from some illegal brain dump site or as a
result of failing the exam and taking note of some of the
questions. In any case, please do not "feed" these types
of people with any help, as you are inadvertently ruining
the MCSD program for the rest of us.

No doubt Microsoft will be monitoring this topic with
interest.

Thank you.

channel is being created with no name specified, so the
default name is "http". If another HTTP channel had been
created first without specifying a name then you would
already have a channel named "http" in the AppDomain.

an AppDomain. By default, the name of an HttpChannel
is "http", and the name of a TcpChannel is "tcp".
Therefore, if you want to register two channels of the
same type, you must specify a different name for one of
them through configuration properties."

the following code to create and register an
HttpServerChannel object to listen at port 8080.

is thrown. Which of the following reasons explains the
exception? (Choose the one correct option.)

information in MSDN on what could be the correct answer.

 

This question is from the Self-Paced Training Kit practice exam that I got
from the Microsoft Official Study Guide "Developing XML Web Services and
Server Components with Microsoft Visual Basic .NET and Microsoft Visual C#
..NET".

Many of of these questions are so poorly worded and/or ambigous.

When I mail my questions to , I never get a reply. So I
post my questions here as this is the only place I can get some kind of
support that Microsoft Press won't provide.

How else am I to get clarification on Microsoft Presss products?

 

Many of of these questions are so poorly worded and/or ambigous.

As many people have said before....

ms are more than likely too embarrassed about the [luck off] content
they hacked together, hence why the y ignore you.

THE BOOKS ARE SHIT, clear enough!!!!

Kline Sphere (Chalk) MCNGP #3

 

No doubt Microsoft will be monitoring this topic with

ROTFLMAO!!!!!

Even if the question(s) were from dumps, can you really see ms taking
an interest!!!!

Kline Sphere (Chalk) MCNGP #3

 

What does ROTFLMAO mean?

 

What does ROTFLMAO mean?

I could tell you, but then I'd have to kill you!

A two second google discovered: -

http://computing-dictionary.thefreedictionary.com/ROTFLMAO

Kline Sphere (Chalk) MCNGP #3