ubasic print modpow(10^9,10^9,1580187223) = ?

Discussion in 'NZ Computing' started by don.lotto@paradise.net.nz, Jul 22, 2007.

  1. Guest

    ubasic print modpow(10^9,10^9,1580187223) = ?

    divides billion ^ billion +3.
    sci.math 2000.

    don.lotto nz 22/7/07 pi-day.
     
    , Jul 22, 2007
    #1
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  2. XPD Guest

    <> wrote in message
    news:...
    > ubasic print modpow(10^9,10^9,1580187223) = ?
    >
    > divides billion ^ billion +3.
    > sci.math 2000.
    >
    > don.lotto nz 22/7/07 pi-day.
    >



    ???
     
    XPD, Jul 22, 2007
    #2
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  3. lolinternet Guest

    XPD wrote:
    >> <> wrote in message
    >> \gibberish/

    >
    > ???


    o/

    I think this is how he signals the alternate beings that he's due for
    his next probe.
     
    lolinternet, Jul 22, 2007
    #3
  4. "lolinternet" <> wrote in message
    news:...
    > XPD wrote:
    >>> <> wrote in message \gibberish/

    >>
    >> ???

    >
    > o/
    >
    > I think this is how he signals the alternate beings that he's due for his
    > next probe.


    I've read don.lotto's posts in nz.comp for quite a while and maybe don can
    actually post a message in english without all the maths involved one day
    and without putting the date of when he posted it in his message.

    No one ever replies back to his posts without flame in nz.comp and are they
    questions or statements as he keeps using ?'s all the time. Does he expect
    people to reply back to them or does he just like writing statements without
    explaining himself?

    Maybe don can enlighten us why he has to posts his maths questions in
    nz.comp are does anyone actually get any enjpyment out of them?

    Thanks
     
    Craig Whitmore, Jul 22, 2007
    #4
  5. Dana Guest

    > modpow(10^9,10^9,1580187223) = ?

    If I follow, here's Mathematica's answer:

    PowerMod[1000000000, 1000000000, 1580187223]

    1580187220

    --
    HTH
    Dana


    <> wrote in message
    news:...
    > ubasic print modpow(10^9,10^9,1580187223) = ?
    >
    > divides billion ^ billion +3.
    > sci.math 2000.
    >
    > don.lotto nz 22/7/07 pi-day.
    >
     
    Dana, Jul 23, 2007
    #5
  6. Guest

    On Jul 23, 1:38 pm, "Dana" <> wrote:
    > > modpow(10^9,10^9,1580187223) = ?

    >
    > If I follow, here's Mathematica's answer:
    >
    > PowerMod[1000000000, 1000000000, 1580187223]
    >
    > 1580187220
    >
    > --
    > HTH
    > Dana


    many thx,
    Quite Right I think.

    casio fx 82 ms schools scicalc

    10 ^ (9e9) STO A

    A / (A / ANS +2
    = = = ....

    integer result after 700 million steps.

    >
    > <> wrote in message
    >
    > news:...
    >
    >
    >
    > > ubasic print modpow(10^9,10^9,1580187223) = ?

    >
    > > divides billion ^ billion +3.
    > > sci.math 2000.

    >
    > > don.lotto nz 22/7/07 pi-day.- Hide quoted text -

    >
    > - Show quoted text -


    don.mcdonald nz
     
    , Jul 31, 2007
    #6
  7. Dana Guest

    > integer result after 700 million steps.

    Hi. PowerMod function uses a number theory method to solve this in only a
    few loops.
    It avoids the actual calculation of x^y, which can be very large.
    If you do a search, you may be able to find the actual method.
    Good luck. :>)
    --
    Dana


    <> wrote in message
    news:...
    > On Jul 23, 1:38 pm, "Dana" <> wrote:
    >> > modpow(10^9,10^9,1580187223) = ?

    >>
    >> If I follow, here's Mathematica's answer:
    >>
    >> PowerMod[1000000000, 1000000000, 1580187223]
    >>
    >> 1580187220
    >>
    >> --
    >> HTH
    >> Dana

    >
    > many thx,
    > Quite Right I think.
    >
    > casio fx 82 ms schools scicalc
    >
    > 10 ^ (9e9) STO A
    >
    > A / (A / ANS +2
    > = = = ....
    >
    > integer result after 700 million steps.
    >
    >>
    >> <> wrote in message
    >>
    >> news:...
    >>
    >>
    >>
    >> > ubasic print modpow(10^9,10^9,1580187223) = ?

    >>
    >> > divides billion ^ billion +3.
    >> > sci.math 2000.

    >>
    >> > don.lotto nz 22/7/07 pi-day.- Hide quoted text -

    >>
    >> - Show quoted text -

    >
    > don.mcdonald nz
    >
     
    Dana, Jul 31, 2007
    #7
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