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calculation on lists

 
 
loïc Lauréote
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      12-19-2012

Thank for your answer,

I found something allowing to avoid loops.
I use operator overloading.


import math

class Vector:
def __init__(self, x=0, y=0):
self.x=x
self.y=y
def __eq__(self, vB): return (self.x==vB.x) and (self.y==vB.y)
def __add__(self, vB): return Vector(self.x+vB.x,self.y+vB.y)
def __sub__(self, vB): return Vector(self.x-vB.x,self.y-vB.y)
def __mul__(self, c):
if isinstance(c,Vector): return Vector(self.x*c.x,self.y*c.y)
else: return Vector(c*self.x,c*self.y)


def __div__(self, c):
if isinstance(c,Vector): return Vector(self.x/c.x,self.y/c.y)
else: return Vector(c*self.x,c*self.y)



a = Vector(4,5)
b = Vector(6,7)
print a,b
print b*b+a


thx


> Date: Wed, 19 Dec 2012 13:38:28 +0100
> Subject: Re: calculation on lists
> From: http://www.velocityreviews.com/forums/(E-Mail Removed)
> To: (E-Mail Removed)
> CC: (E-Mail Removed)
>
> 2012/12/19 loïc Lauréote <(E-Mail Removed)>:
> hi,
> I
> have a question,
> is there a tool to calculate on list ?
>
> something like :
>
> >a= [1,1,1,1]
> >b = [5,9,8,4]
> >c = a+b*a
> >print c
> >[6,10,9,5]

>
> Thx
>
> ======
>
> Hi,
> for such simpler cases, you may try list comprehensions and probably
> the zip(...) function
>
> >>> [a+b*a for a,b in zip([1,1,1,1], [5,9,8,4])]

> [6, 10, 9, 5]
> >>>

>
> hth,
> vbr


 
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