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On 30.09.2012 08:49, eggie5 wrote:
> Can somebody please suggest a getter way of doing this? Did you mean "better"? > hmac = "0000000000000000000000000000000000000000" > #40 is length of hmac > #255 is values of each byte to try > (0..40).step(2) do |i| > (0..255).each do |j| > hmac[i..i+1]="%02x" % j > p hmac > end > end > > > It just iterates all the values of a 20 byte array as a string from left to right. e.g.: > > 000000000000000000000000000000000000000 > 0100000000000000000000000000000000000000 > 0200000000000000000000000000000000000000 > . > . > . > FD00000000000000000000000000000000000000 > FE00000000000000000000000000000000000000 > FF00000000000000000000000000000000000000 > . > . > . > FFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFFF > (2**(20*  ).times {|x| printf "%040x\n", x}You get a different order though. What do you need that for? robert -- remember.guy do |as, often| as.you_can - without end http://blog.rubybestpractices.com/ |
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