«

Hi,

I have a question about proc object and block.

I tried the following code:

pr = proc do
yield "hom"
end

pr.call do |arg|
p arg
end

What I expected is:

$ ruby homhom.rb
hom

But I got:

$ ruby homhom.rb
homhom.rb:2:in `block in <main>': no block given (yield)
(LocalJumpError)
from homhom.rb:5:in `call'
from homhom.rb:5:in `<main>'
$ ruby -v
ruby 1.9.3p0 (2011-10-30 revision 33570) [x86_64-darwin10.8.0]

Is it impossible to pass block to proc object?

--
makoto kuwata

On 04/22/2012 05:43 AM, makoto kuwata wrote:
> Hi,
>
> I have a question about proc object and block.
>
> I tried the following code:
>
> pr = proc do
> yield "hom"
> end
>
> pr.call do |arg|
> p arg
> end
>
> What I expected is:
>
> $ ruby homhom.rb
> hom
>
> But I got:
>
> $ ruby homhom.rb
> homhom.rb:2:in `block in<main>': no block given (yield)
> (LocalJumpError)
> from homhom.rb:5:in `call'
> from homhom.rb:5:in `<main>'
> $ ruby -v
> ruby 1.9.3p0 (2011-10-30 revision 33570) [x86_64-darwin10.8.0]
>
> Is it impossible to pass block to proc object?

The only way I am aware of ATM is explicit:

irb(main):003:0> pr = lambda {|bl| bl.call "hom" }
=> #<Proc:0x829cd74@(irb):3 (lambda)>
irb(main):004:0> pr.call lambda {|x| p x}
"hom"
=> "hom"

Kind regards

robert