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I've created a custom type named person:

function person(name, age) {this.name=name; this.age=age;}

Now, how to create an array (of 10 elements) of that new type?
[10]person

Archos wrote:
> I've created a custom type named person:
>
> function person(name, age) {this.name=name; this.age=age;}
>
> Now, how to create an array (of 10 elements) of that new type?
> [10]person

var persons = [
new person("name 1", 1),
new person("name 2", 2),
new person("name 3", 3),
...
];

Arrays in Javascript don't have a particular type of elements however so
you could freely mix your type with other types in a single array.


--

Martin Honnen --- MVP Data Platform Development
http://msmvps.com/blogs/martin_honnen/

Denis McMahon wrote:

> On Sun, 22 Jan 2012 03:55:03 -0800, Archos wrote:
>> I've created a custom type named person:
>>
>> function person(name, age) {this.name=name; this.age=age;}
>>
>> Now, how to create an array (of 10 elements) of that new type?
>> [10]person
>
> Not tested, but maybe you could start with something like:
>
> var i=10;var a=new array();while(i--)a[i]=new person("",0);
>
> and work out why it doesn't work (because it probably won't).

Will you *please* stop wasting everybody's time by posting obviously
erroneous solutions?

Lack of code style aside, this works fine if you have that basic knowledge
that it is `new Array' in ECMAScript implementations (case-sensitive). The
easier, today irrelevantly less compatible expression is, of course, the
empty Array initializer, `[]'.

As `person' refers to a constructor, the identifier in the declaration and
call should be `Person' by good convention, of course.


PointedEars
--
When all you know is jQuery, every problem looks $(olvable).