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How do I place a function outside of the, so called, "class" in
prototype.js?

Example: Here is a standard way to write a class using prototype.js.

var Person = Class.create({
initialize: function(name) {
this.name = name;
},
say: function(message) {
return this.name + ': ' + message;
}
});

I want the function "say" to be outside of class like:

var Person = Class.create({
initialize: function(name) {
this.name = name;
},
say : sayOutside // <-------moved out
});

function sayOutside(message) {
return this.name + ': ' + message;
}

On Dec 5, 6:27 am, VUNETdotUS <vunet...@gmail.com> wrote:
> How do I place a function outside of the, so called, "class" in
> prototype.js?

Questions specifically related to features or usage of particular
libraries are off-topic here, you should try a Prototype.js news
group, e.g.:

<URL: http://groups.google.com.au/group/ru...s?hl=en&lnk=li
>

Also, it matters a great deal which version of Prototype.js you are
using - the Class object was changed significantly in version 1.6 in
an attempt to model classic OO inheritance.

You will need to specify whether you want to retain the inheritance
features, or circumvent them.

>
> Example: Here is a standard way to write a class using prototype.js.
>
> var Person = Class.create({
> initialize: function(name) {
> this.name = name;
> },
> say: function(message) {
> return this.name + ': ' + message;
> }
>
> });
>
> I want the function "say" to be outside of class like:
>
> var Person = Class.create({
> initialize: function(name) {
> this.name = name;
> },
> say : sayOutside // <-------moved out
>
> });
>
> function sayOutside(message) {
> return this.name + ': ' + message;
>
> }

You can use Object.extend, something like:

Object.extend(Person, {say: sayOutside});

but it simply copies properties and values from one objet to another,
which to me just makes it obfuscation and is no different to:

Person.say = sayOutside;

but you may want to use:

Person.prototype.say = sayOutside;

Whatever.


--
Rob

On Dec 4, 4:22 pm, Randy Webb <HikksNotAtH...@aol.com> wrote:
> VUNETdotUS said the following on 12/4/2007 3:27 PM:
>
> > How do I place a function outside of the, so called, "class" in
> > prototype.js?
>
> You go to one of the prototype forums (search the archives) and ask
> someone who supports it how to do what you want.
>
> --
> Randy
> Chance Favors The Prepared Mind
> comp.lang.javascript FAQ -http://jibbering.com/faq/index.html
> Javascript Best Practices -http://www.JavascriptToolbox.com/bestpractices/

I'll try their forums. However I thought Prototype is just a JS with
functions and methods to simplify stuff. I wonder how do JS experts
treat prototype anyway?

On Dec 5, 11:25 am, VUNETdotUS <vunet...@gmail.com> wrote:
> On Dec 4, 4:22 pm, Randy Webb <HikksNotAtH...@aol.com> wrote:
>
> > VUNETdotUS said the following on 12/4/2007 3:27 PM:
>
> > > How do I place a function outside of the, so called, "class" in
> > > prototype.js?
>
> > You go to one of the prototype forums (search the archives) and ask
> > someone who supports it how to do what you want.
>
> > --
> > Randy
> > Chance Favors The Prepared Mind
> > comp.lang.javascript FAQ -http://jibbering.com/faq/index.html
> > Javascript Best Practices -http://www.JavascriptToolbox.com/bestpractices/
>
> I'll try their forums. However I thought Prototype is just a JS with
> functions and methods to simplify stuff. I wonder how do JS experts
> treat prototype anyway?

Like a red-headed stepchild.