«

Why is this converted to a string???
var newidNumber =((idNumber/2).toFixed())+1;

Thanks
Mike

On Nov 28, 4:35 pm, Mike <ampel...@gmail.com> wrote:
> Why is this converted to a string???
> var newidNumber =((idNumber/2).toFixed())+1;

Because the - toFixed - method returns a string.

On Nov 28, 10:37 am, Henry <rcornf...@raindrop.co.uk> wrote:
> On Nov 28, 4:35 pm, Mike <ampel...@gmail.com> wrote:
>
> > Why is this converted to a string???
> > var newidNumber =((idNumber/2).toFixed())+1;
>
> Because the - toFixed - method returns a string.

when you want to use the variable as a number use eval() to return a
number

On Nov 28, 4:45 pm, kendalk08 <kendal...@gmail.com> wrote:
> On Nov 28, 10:37 am, Henry <rcornf...@raindrop.co.uk> wrote:
>
> > On Nov 28, 4:35 pm, Mike <ampel...@gmail.com> wrote:
>
> > > Why is this converted to a string???
> > > var newidNumber =((idNumber/2).toFixed())+1;
>
> > Because the - toFixed - method returns a string.
>
> when you want to use the variable as a number use eval() to
> return a number

No thanks, I will use the unary plus operator, the Number constructor
called as a function, parseInt or parseFloat, depending on the
situation. The - eval - function would be the absolute worst method to
use, particularly as its behaviour is unpredictable whenever its
argument is a string that does not represent a number.

On Nov 28, 10:56 am, Henry <rcornf...@raindrop.co.uk> wrote:
> On Nov 28, 4:45 pm, kendalk08 <kendal...@gmail.com> wrote:
>
> > On Nov 28, 10:37 am, Henry <rcornf...@raindrop.co.uk> wrote:
>
> > > On Nov 28, 4:35 pm, Mike <ampel...@gmail.com> wrote:
>
> > > > Why is this converted to a string???
> > > > var newidNumber =((idNumber/2).toFixed())+1;
>
> > > Because the - toFixed - method returns a string.
>
> > when you want to use the variable as a number use eval() to
> > return a number
>
> No thanks, I will use the unary plus operator, the Number constructor
> called as a function, parseInt or parseFloat, depending on the
> situation. The - eval - function would be the absolute worst method to
> use, particularly as its behaviour is unpredictable whenever its
> argument is a string that does not represent a number.

You probably know more about Javascript, but I have been coding for
about 2 years and the - eval - function has always worked for me.

On Nov 28, 4:57 pm, kendalk08 wrote:
> On Nov 28, 10:56 am, Henry wrote:
<snip>
>>> when you want to use the variable as a number use eval() to
>>> return a number
<snip>
>> ... . The - eval - function would be the absolute worst method to
>> use, particularly as its behaviour is unpredictable whenever its
>> argument is a string that does not represent a number.
>
> You probably know more about Javascript,

You suggested using - eval - so we are well past "probably".

> but I have been coding for about 2 years

It might be an idea to stop and RTFM soonish.

> and the - eval -
> function has always worked for me.

Even the worst ways of doing things 'work', otherwise they become the
best ways of not doing them.

On Nov 28, 12:06 pm, Henry <rcornf...@raindrop.co.uk> wrote:
> On Nov 28, 4:57 pm, kendalk08 wrote:
>
> > On Nov 28, 10:56 am, Henry wrote:
> <snip>
> >>> when you want to use the variable as a number use eval() to
> >>> return a number
> <snip>
> >> ... . The - eval - function would be the absolute worst method to
> >> use, particularly as its behaviour is unpredictable whenever its
> >> argument is a string that does not represent a number.
>
> > You probably know more about Javascript,
>
> You suggested using - eval - so we are well past "probably".
>

There are such things as manners--this sentence was probably
unnecessary.

On Nov 29, 3:00 am, Randy Webb <HikksNotAtH...@aol.com> wrote:
> kendalk08 said the following on 11/28/2007 11:45 AM:
>
> > On Nov 28, 10:37 am, Henry <rcornf...@raindrop.co.uk> wrote:
> >> On Nov 28, 4:35 pm, Mike <ampel...@gmail.com> wrote:
>
> >>> Why is this converted to a string???
> >>> var newidNumber =((idNumber/2).toFixed())+1;
> >> Because the - toFixed - method returns a string.
>
> > when you want to use the variable as a number use eval() to return a
> > number
>
> Who fed you that line of incompetent ignorant crap?

You mean you know a script engine where eval("2") doesn't return
typeof "number"? Which one is that (non-ECMAScript compliant by
default)?

If you foresee some dangerous consequences of eval("2") in comparison
of the +"2" trick then you should spell them for the public attention
IMHO. After all eval is not a sex with underagers or drugs to get
berserk on the combination of these four letters by itself, IMHO.

On Nov 29, 12:25 pm, Randy Webb <HikksNotAtH...@aol.com> wrote:
> > You mean you know a script engine where eval("2") doesn't return
> > typeof "number"?
>
> Who said I did? I didn't. Anybody that uses eval(string) to convert
> string to a number is an incompetent ignorant idiot.

And anyone who uses instead +"2" trick instead is a highly intelligent
experienced master who's even sh** smells just like roses?

Cool... Got it... Some men are so easy to please, really