«

Hi all,

I'm looking for a regular expression that can do the following:

if matches: a~b§c~d
replace by: a~§c~

Sorry for posting something so stupid but I can't understand a word on
regexp

Thanks in advance,

Fabian Vilers wrote on 06 feb 2006 in comp.lang.javascript:

> Hi all,
>
> I'm looking for a regular expression that can do the following:
>
> if matches: a~b§c~d
> replace by: a~§c~
>
> Sorry for posting something so stupid but I can't understand a word on
> regexp

If you do not understand, how would you possibly know it is stupid,
or that regex would be a good solution?

At least you would have to declare what you mean by ~ and §.

As I read it now, this code will do what you ask:

s = 'a~b§c~d'
alert(s)
s = 'a~§c~'
alert(s)



--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

>if matches: a~b§c~d
>replace by: a~§c~

If to take your sample as real data:

var s = "bla-bla~b§c~done";
var s1 = s.replace(/a~b§c~d/g, "a~§c~");

But if it is only sample I agree with Evertjan: you would have to
declare what you mean by ~ and §.

marss wrote:

> But if it is only sample I agree with Evertjan: you would have to
> declare what you mean by ~ and §.
>

Thanks all.

I can give you more explanation here.

I've a string containing this:

var data_table =
'Magenta~RECUP;Khaki~ANC;Magenta~RECUP§Khaki~ANC!K haki~ANC;Magenta~RECUP§Red~MAL;Magenta~RECUP§PaleG reen~CF§Khaki~ANC';

What I need is:

If the regexp matches a~b§c~d, where a, b, c, d can be any combination
of letters, replace it by a~§c~ or said differently, drop b and d.

Am I much clear with theses information?

Thanks again in advance for helping,

> 'Magenta~RECUP;Khaki~ANC;Magenta~RECUP§Khaki~ANC!K haki~ANC;Magenta~RECUP§Red~MAL;Magenta~RECUP§PaleG reen~CF§Khaki~ANC';
>

var s =
"Magenta~RECUP;Khaki~ANC;Magenta~RECUP§Khaki~ANC!K haki~ANC;Magenta~RECUP§Red~MAL;Magenta~RECUP§PaleG reen~CF§Khaki~ANC";
var s1 = s.replace(/(\w*~)\w*(\§\w*~)\w*/g, "$1$2");


> What I need is:
>
> If the regexp matches a~b§c~d, where a, b, c, d can be any combination
> of letters, replace it by a~§c~ or said differently, drop b and d.
>

But it is not clearly stated what to do when we have a~b§c~d§e~f
pattern (your data string ends with
Magenta~RECUP§PaleGreen~CF§Khaki~ANC')

marss wrote:

> var s1 = s.replace(/(\w*~)\w*(\§\w*~)\w*/g, "$1$2");

Thanks! You're a regexp god

>
> But it is not clearly stated what to do when we have a~b§c~d§e~f
> pattern (your data string ends with
> Magenta~RECUP§PaleGreen~CF§Khaki~ANC')
>

Yes, forgot to say

I can have 4 possibilities:
- a~b
- a~b§c~d
- a~b§c~d§e~f
- a~b§c~d§e~f§g~h

If it's one the last three, b, d, f and h must be removed.

How can I change the regexp?

Fabian Vilers wrote on 06 feb 2006 in comp.lang.javascript:

> marss wrote:
>
>> var s1 = s.replace(/(\w*~)\w*(\§\w*~)\w*/g, "$1$2");
>
> Thanks! You're a regexp god
>
>>
>> But it is not clearly stated what to do when we have a~b§c~d§e~f
>> pattern (your data string ends with
>> Magenta~RECUP§PaleGreen~CF§Khaki~ANC')
>>
>
> Yes, forgot to say
>
> I can have 4 possibilities:
> - a~b
> - a~b§c~d
> - a~b§c~d§e~f
> - a~b§c~d§e~f§g~h
>
> If it's one the last three, b, d, f and h must be removed.
>
> How can I change the regexp?
>

This still is not right.

We should know what the first letter not in the string after b,d,f or h is

Or:

a~b§c~da~b§c~d

what is the delimiter between d and a?

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

Evertjan. wrote:
> a~b§c~da~b§c~d
>
> what is the delimiter between d and a?
>

It depends. It could be either a '!' or a ';'.

In fact, a got a lot of information inside a string. My problem (see
other post) is that I worked with the string splited into arrays. But
looping in these arrays was throwing the warning message box about
infinite loops.

Fabian Vilers wrote on 06 feb 2006 in comp.lang.javascript:

> Evertjan. wrote:
>> a~b§c~da~b§c~d
>>
>> what is the delimiter between d and a?
>>
>
> It depends. It could be either a '!' or a ';'.

Please always specify fully!

> In fact, a got a lot of information inside a string. My problem (see
> other post) is that I worked with the string splited into arrays. But
> looping in these arrays was throwing the warning message box about
> infinite loops.
>


<script type='text/javascript>

var s =
"Magenta~RECUP;Khaki~ANC;Magenta~RECUP§Khaki~ANC!K haki~ANC;"+
"Magenta~RECUP§Red~MAL;Magenta~RECUP§PaleGreen~CF§ Khaki~ANC";

s = s.replace(/([^~§!;]+~)[^~§!;]+([~§!;]||$)/g,'$1$2')

alert(s)

</script>

--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)

Evertjan. wrote on 06 feb 2006 in comp.lang.javascript:

> Fabian Vilers wrote on 06 feb 2006 in comp.lang.javascript:
>
>> Evertjan. wrote:
>
> <script type='text/javascript>
>
> var s =
> "Magenta~RECUP;Khaki~ANC;Magenta~RECUP§Khaki~ANC!K haki~ANC;"+
> "Magenta~RECUP§Red~MAL;Magenta~RECUP§PaleGreen~CF§ Khaki~ANC";
>
> s = s.replace(/([^~§!;]+~)[^~§!;]+([~§!;]||$)/g,'$1$2')

Even simpler, just delete anything between ~ and § or ! or ; or EOL:

s = s.replace(/~[^~§!;]+([§!;]||$)/g,'~$1')


> alert(s)
>
> </script>
>



--
Evertjan.
The Netherlands.
(Please change the x'es to dots in my emailaddress)