«

Hi all

// my code
var string1= "Pablo has 3 cats and 1 dog";
var string2= "Pablo has 3 cats";
var str1 = "";
var str2 = "";


str1 = string1.match(string1, "g");
str2 = string2.match(string1, "g");

if (str1 == str2) // STRING IS NOT the same , what is wrong ???
{
app.alert("String are the same ");
}
else
{
app.alert("String is different...");
}

I want to compare two strings in 'if' statement, which are asssigned to
variables, If I compare two variable which have assigned the same (in
my opinion) string after RegExp match function the string is different
unfortunatellly

but when I compare in 'if' statement:
if( str1 == "Pablo has 3 cats") or
if( str2 == "Pablo has 3 cats") or
if("Pablo has 3 cats" == str2) or
if("Pablo has 3 cats" == str2)
THIS COMPARISON IS WORKING WELL and strings is the same


I wonder why my string is not the same ???
the match function returned me the same string for str1 and str2
variable when I invoke alert funtion on it, but for 'if' statement the
string is not the same , what is wrong ???

"Ptaku25" <> wrote in message
news: ups.com...
> Hi all
>
> // my code
> var string1= "Pablo has 3 cats and 1 dog";
> var string2= "Pablo has 3 cats";
> var str1 = "";
> var str2 = "";
>
>
> str1 = string1.match(string1, "g");
> str2 = string2.match(string1, "g");

[snip]

Why are you using ".match()"?

match Method :

Returns, as an array, the results of a search on a string using a supplied
Regular Expression object.

On 12/01/2006 15:25, Ptaku25 wrote:

> // my code
> var string1= "Pablo has 3 cats and 1 dog";
> var string2= "Pablo has 3 cats";
> var str1 = "";
> var str2 = "";
>
> str1 = string1.match(string1, "g");
> str2 = string2.match(string1, "g");

Whatever it is you're trying to do, you're going about it the wrong way.
The String.prototype.match method takes only one argument, and that
argument is a regular expression.

Start by explaining /exactly/ what you're trying to achieve. You mention
strings being the 'same', but string1 and string2 clearly aren't. Are
you trying to identify substrings?

[snip]

Mike

--
Michael Winter
Prefix subject with [News] before replying by e-mail.

Michael Winter napisal(a):
> On 12/01/2006 15:25, Ptaku25 wrote:
>
> > // my code
> > var string1= "Pablo has 3 cats and 1 dog";
> > var string2= "Pablo has 3 cats";
> > var str1 = "";
> > var str2 = "";
> >
> > str1 = string1.match(string1, "g");
> > str2 = string2.match(string1, "g");
>
> Whatever it is you're trying to do, you're going about it the wrong way.
> The String.prototype.match method takes only one argument, and that
> argument is a regular expression.
>
> Start by explaining /exactly/ what you're trying to achieve. You mention
> strings being the 'same', but string1 and string2 clearly aren't. Are
> you trying to identify substrings?


Yes I would like to identify substring!,
and as I underdstand, I going to wrong way using match() method???

Which method or tricks I should use to make identyfication some
substring in any string???





>
> [snip]
>
> Mike
>
> --
> Michael Winter
> Prefix subject with [News] before replying by e-mail.

Ptaku25 wrote:

> [...]
> Which method or tricks I should use to make identyfication some
> substring in any string???

Use `string1.indexOf(...)' or `new RegExp("...").test(string1)' or
`/.../.test(string1)'

> [...]

and learn to quote.


PointedEars

Ptaku25 wrote:
> Michael Winter napisal(a):
>
>>On 12/01/2006 15:25, Ptaku25 wrote:
>>
>>
>>>// my code
>>>var string1= "Pablo has 3 cats and 1 dog";
>>>var string2= "Pablo has 3 cats";
>>>var str1 = "";
>>>var str2 = "";
>>>
>>>str1 = string1.match(string1, "g");
>>>str2 = string2.match(string1, "g");
>>
>>Whatever it is you're trying to do, you're going about it the wrong way.
>>The String.prototype.match method takes only one argument, and that
>>argument is a regular expression.
>>
>>Start by explaining /exactly/ what you're trying to achieve. You mention
>>strings being the 'same', but string1 and string2 clearly aren't. Are
>>you trying to identify substrings?
>
>
>
> Yes I would like to identify substring!,
> and as I underdstand, I going to wrong way using match() method???
>
> Which method or tricks I should use to make identyfication some
> substring in any string???
>

var string1= "Pablo has 3 cats and 1 dog";
var string2= "Pablo has 3 cats";


See if string2 is anywhere in string1:

var x = new RegExp(string2).test(string1);
// x is a boolean with value 'true'


Get all instances of string2 in string1:

var x = string1.match(new RegExp(string2, 'g'));
// x is an array of length 1 and value: ['Pablo has 3 cats']


Get all instances of 'a' followed by a character in string1:

var x = string1.match(new RegExp('a.','g'));
// x is an array, length 4, value: ['ab', 'as', 'at', 'an']


Regular expressions are almost a language of their own.


--
Rob

Hi,

>
> // my code
> var string1= "Pablo has 3 cats and 1 dog";
> var string2= "Pablo has 3 cats";
[snip]
> else
> {
> app.alert("String is different...");
> }
>
> I want to compare two strings in 'if' statement, which are asssigned to
> variables, If I compare two variable which have assigned the same (in
> my opinion) string after RegExp match function the string is different
> unfortunatellly
>

humm you could use ASTUce framework Assertions methods to
test the equality of your strings

using
<script type="text/javascript" src="lib/core2_v1.0.1_JS.js"></script>
<script type="text/javascript" src="lib/ASTUce_v1.0.0.js"></script>
....

you could simply write that

var Assertion = buRRRn.ASTUce.Assertion;

var string1 = "Pablo has 3 cats and 1 dog";
var string2 = "Pablo has 3 cats";

try
{
Assertion.assertEquals( string1, string2 );
}
catch( e )
{
trace( e );
}

and obtain that

## ComparisonFailure : expected:<... and 1 dog> but was:<...> ##


you can find more info here:
http://www.burrrn.com/projects/ASTUce.html

and a basic tutorial here for unit testing your code:
http://www.zwetan.com/blog/buRRRn/AS...avaScript.html

if you re only interested in the code comparing 2 strings for their
difference look the source code here
and adapt to your need
http://live.burrrn.com/browser/ECMA-...isonFailure.es

HTH
zwetan