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A gentleman in this forum gave me this code and it work great to test
that a string consist of only digits and it is 8 character long.

(!/^\d{8}$/.test(ContactNo) )

How do I modify the above if I want the string to be of any length but
consist of only digits?

Thanks

<> wrote
> A gentleman in this forum gave me this code and it work great to test
> that a string consist of only digits and it is 8 character long.
>
> (!/^\d{8}$/.test(ContactNo) )
>
> How do I modify the above if I want the string to be of any length but
> consist of only digits?

Change the three characters "{8}" into "{1,}" or into a single "+" sign.

Or divide by 2 and see if it 's still a number...

Or...
--
Ivo

Thanks, the code worked.

I was just wondering, if you could explain how the syntax of the test
is actually constructed? I would be highly appreciative.

Regards

wrote:
> Thanks, the code worked.
>
> I was just wondering, if you could explain how the syntax of the test
> is actually constructed? I would be highly appreciative.
>
> Regards
>
Please quote the prevous posting...


[Regular Expression Here].test("String Here")
returns true or false


alert(/^\d+$/.test("123")) //true
alert(/^\d+$/.test("123a")) //false

if(/^\d+$/.test(yourValue)){
//good input, do stuff with it
} else{
//bad input
}
Mick

wrote:
> Thanks, the code worked.
>
> I was just wondering, if you could explain how the syntax of the test
> is actually constructed? I would be highly appreciative.
>
> Regards

Apologies to Ivo...

Regular expression:

/ ---> delimeter (like quotes for a string, marks start & end)
^ ---> pattern must start at very beginning of sample string
\d ---> metacharacter, matches one digit (0-9)
+ ---> quantifier, specifies one or more of the preceding
(and replaces the {8}, which specifies exactly eight;
{3,8}, e.g., would require between 3 and 8; {2,} requires at least two
or more; '*' signifies zero or more, '?' is zero or one (i.e.,
optional)
$ ---> pattern must match to the end of sample string
/ ---> closing delimeter

So: this will match a string that contains one or more digits. And
nothing else. The exclamation mark before the call to test() 'flips'
the result: if the test fails, false becomes true, which triggers the
error message, etc.

http://www.webreference.com/js/column5/index.html

....yikes.... #

* delimiter *

RobB wrote:

> ...yikes.... #
>
> * delimiter *
>

delimeter: Measures popularity of sandwich shops...
Mick

Mick White wrote:
> RobB wrote:
>
> > ...yikes.... #
> >
> > * delimiter *
> >
>
> delimeter: Measures popularity of sandwich shops...
> Mick

No, no, no...weighs the pastrami, bro' ! #

> Thank you for the explanation. It does seem that this test is only to
> determine that a string contains only numbers. Can I use this test to
> make sure that a string contain alphabets and numbers with no special
> character?

You can use "a test" (not "this test"), a "Regular Expression" test, to
do what you want, and more. All you have to do is learn about "Regular
Expressions". You've been pointed in the right direction. Now you can
google for tutorials on the topic.

Effendi Baba wrote:
> Rob
>
> Thank you for the explanation. It does seem that this test is only to
> determine that a string contains only numbers. Can I use this test to
> make sure that a string contain alphabets and numbers with no special
> character?
>

Please don't top-post.

Play with this:

<input type="text" onblur="checkMe(this.value);">

<script type="text/javascript">
function checkMe(x){
alert(!/\W+/.test(x));
}
</script>


\W matches any non-word character (i.e. not a-z A-Z or 0-9).
Putting ! in front negates the test, so if it finds one or more
non-word characters, it returns false.

Here is a reference here to help you learn RegExp:

<URL:http://www.webreference.com/js/column5/>

--
Rob