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indent based on stack

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I am doing this for each subroutine.
print 'START.' . (caller(0))[3] . "\n"; and
print 'END.' . (caller(0))[3] . "\n";

What I would like to do is add a space after the START. for each level
down the stack it is.

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Tim McDaniel
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In article <(E-Mail Removed)>,
bjlockie <(E-Mail Removed)> wrote:
>I am doing this for each subroutine.
>print 'START.' . (caller(0))[3] . "\n"; and
>print 'END.' . (caller(0))[3] . "\n";
>What I would like to do is add a space after the START. for each level
>down the stack it is.
> END.3
> END.2

([3] is the name of the subroutine, so 1, 2, and 3 above represent
subroutine names.)

A little experimentation shows that caller(N) returns a zero-length
list when N is larger than the number of layers of call. So you can
loop, calling "my @a = caller($i);" until scalar @a == 0.
The "x" operator, for A x B, returns a string being B copies of the
string value of A, so ' ' x $n returns a string of $n spaces.

Tim McDaniel, Removed)

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