«

Hi

In the following sequence

$r = {}; # a hashref
$r = []; # an arrayref
$r = ?; # a scalar ref

What is ? ? I want to pass a ref to a scalar (pass by reference)
without resorting to

my $r;
mySub( \$r );

I just want to use

my $r = (something);
mySub( $r );

to be consistent with

my $r = {}; # or my $r = [];
mySub( $r );

I know it's not a big drama on the surface, but I'm trying to overload
the method to return various results depending on the reference type,
and I dont want the \ in some calls and not others.

Thanks

Chet Butcher <> wrote:

> In the following sequence
>
> $r = {}; # a hashref
> $r = []; # an arrayref
> $r = ?; # a scalar ref
>
> What is ? ?


Troll alert!

This was posted here in August 2006 and again last January...


--
Tad McClellan
email: perl -le "print scalar reverse qq/moc.noitatibaher\100cmdat/"

Chet Butcher <> writes:
> In the following sequence
>
> $r = {}; # a hashref
> $r = []; # an arrayref
> $r = ?; # a scalar ref
>
> What is ? ? I want to pass a ref to a scalar (pass by reference)
> without resorting to
>
> my $r;
> mySub( \$r );
>
> I just want to use
>
> my $r = (something);
> mySub( $r );
>
> to be consistent with
>
> my $r = {}; # or my $r = [];
> mySub( $r );
>
> I know it's not a big drama on the surface, but I'm trying to overload
> the method to return various results depending on the reference type,
> and I dont want the \ in some calls and not others.

Why did you redirect followups to comp.lang.c?

--
Keith Thompson (The_Other_Keith) kst- <http://www.ghoti.net/~kst>
Nokia
"We must do something. This is something. Therefore, we must do this."
-- Antony Jay and Jonathan Lynn, "Yes Minister"

Chet Butcher <> writes:
[SNIP - nothing of interest to the newsgroup where you directed follow-ups]

Hello "tea pot". You're still an idiot, even after you've morphed.
What a sad and sorry life you must lead.

Phil
--
Marijuana is indeed a dangerous drug.
It causes governments to wage war against their own people.
-- Dave Seaman (sci.math, 19 Mar 2009)