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Hi

Is there a nice way of formatting a decimal to have a fixed number of
trailing zero's?
I am decimalising some data to feed into another application. The input
requires 6 decimal places.
Using sprintf I can apply various formats, like leading zero's but can't
figure out how to add trailers...

For most of my data it's not a problem, but I have a couple of oddities that
divide neatly leading me with 4 decimal places.
One example I have. After conversion I get: 0.1029 but I want 0.102900.

At the moment I am multiplying my variable by 100000 and doing a substr on
the leading 6 characters, but there must be a nicer way than this...

Any help would be much appreciated.

Pete

On Sun, 23 May 2004 19:24:11 +1200, ThePotPlants wrote:

> Hi
>
> Is there a nice way of formatting a decimal to have a fixed number of
> trailing zero's?
> I am decimalising some data to feed into another application. The input
> requires 6 decimal places.
> Using sprintf I can apply various formats, like leading zero's but can't
> figure out how to add trailers...

$ perl -le 'printf "%.6f", 0.1029'
0.102900

Dave...

"ThePotPlants" <> wrote:

: Is there a nice way of formatting a decimal to have a fixed number of
: trailing zero's?

Yes.

: One example I have. After conversion I get: 0.1029 but I want 0.102900.

printf '%.6f', 0.1029

ThePotPlants wrote:
> Is there a nice way of formatting a decimal to have a fixed number of
> trailing zero's?
> I am decimalising some data to feed into another application. The
> input requires 6 decimal places.
> Using sprintf I can apply various formats, like leading zero's but
> can't figure out how to add trailers...

Hmmm, strange.
Doesn't the second example on the sprintf perldoc page work for?

jue

"Dave Cross" <> wrote in message
news...
> On Sun, 23 May 2004 19:24:11 +1200, ThePotPlants wrote:
>
> > Hi
> >
> > Is there a nice way of formatting a decimal to have a fixed number of
> > trailing zero's?
> $ perl -le 'printf "%.6f", 0.1029'
> 0.102900
>
> Dave...

Thanks guys