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hi !

i want to run a script as a cron job on the server, which detects
serveral things.

according to the status, the user shall be informed by displaying a
message in an applet.

does anybody know how to handle that ? i have read something about
sockets but i don't have the knowledge about it. are there perhaps
some scripts available for this task ?

or maybe there is another easier way to do this ?
i can also work with a frame which is permanently refreshed to receive
messages but that's not a good way i think. or ?

it would be nice if anybody can help me in this case. thanks

regards
dirk

maybe you could be a "bit" more specific on what you want to do?

--

greetings,

kodo

[ http://kodo.me.uk ]

kodo <> wrote in message news:<c24uh5$1kp91m$>...
> maybe you could be a "bit" more specific on what you want to do?

thank you that you want to help me

...but i found out how i can do it

the java applet will listen to a socket and the perlscript sends this
message to this socket. so the message can directly displayed in the
applet. i only hava to modify this two parts.

on java side:
import java.net.*;
import java.io.*;

public class Server {

public static void main(String[] args) throws IOException {

String inputLine;

ServerSocket soc = new ServerSocket(6789);
Socket inputsoc = soc.accept();
InputStream is = inputsoc.getInputStream();
InputStreamReader isr = new InputStreamReader(is);
BufferedReader in = new BufferedReader(isr);

while ((inputLine = in.readLine())!=null ) {
System.out.println(inputLine);
}
}
}


on perl side:
use IO::Socket::INET;
$MySocket=new IO::Socket::INET->new(PeerPort=>6789,
Proto=>'tcp',
PeerAddr=>'localhost');
$msg="This is the message";
$MySocket->send($msg);


....but thank you again