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The Perl Cookbook 6.23 has this "bizarre" (to me) statement;

We have found these regular expressions useful or interesting.

Turning \ followed by n into a real newline
s/\\n/\n/g;

When would a \n not be a \n ? The program below sort of simulates that condition, but presumeably there is something else?

Owen

rcook at pcug org au



#----------------------------------------------------
#!/usr/bin/perl -w

use strict;
my $string ="Now is \n the time";
print "$string\n";

$string ='Now is \n the time';
print "$string\n";

(my $newstring = $string) =~ s/\\n/\n/g;
print "$newstring\n";

Now is
the time
Now is \n the time
Now is
the time

Owen wrote:

> The Perl Cookbook 6.23 has this "bizarre" (to me) statement;
>
> We have found these regular expressions useful or interesting.
>
> Turning \ followed by n into a real newline
> s/\\n/\n/g;
>
> When would a \n not be a \n ?
# not a newline
print '\n';
# is a newline
print "\n";