«

It won't work. It's odd. It won't stop and it won't add a number onto x
so it would say
"Roll 1: 5
Roll 2: 3"
etc

It just repeats "Roll 1: (random number)".

Also, is there a way for me to add one to the rand function so it won't
get a zero?

Attachments:
http://www.ruby-forum.com/attachment/5009/dice.rb

--
Posted via http://www.ruby-forum.com/.

On Sep 6, 5:01*pm, Hd Pwnz0r <human.diction...@rocketmail.com> wrote:
> It won't work. It's odd. It won't stop and it won't add a number onto x
> so it would say
> "Roll 1: 5
> Roll 2: 3"
> etc
>
> It just repeats "Roll 1: (random number)".
>
> Also, is there a way for me to add one to the rand function so it won't
> get a zero?
>
> Attachments:http://www.ruby-forum.com/attachment/5009/dice.rb

Next time just put it here:

puts "How many dice do you want to roll?"
roll = gets.chomp
num_rolls = roll
y = 0
x = y.to_i + 1
while x <= roll.to_i
puts "Roll " + x.to_s + ": " + rand(max=6).to_s
end

Take out the gets.chomp:

roll = '12' # gets.chomp

that lets you work on the loop without entering over and over again.

then either fix your while loop by incrementing: x += 1

or use an each loop (which is truly the Ruby way):

(0...roll.to_i).each do |x|
puts 'etc'
end

On Mon, Sep 6, 2010 at 5:01 PM, Hd Pwnz0r
<> wrote:
> It won't work. It's odd. It won't stop and it won't add a number onto x
> so it would say
> "Roll 1: 5
> Roll 2: 3"
> etc
>
> It just repeats "Roll 1: (random number)".
>
> Also, is there a way for me to add one to the rand function so it won't
> get a zero?
>
> Attachments:
> http://www.ruby-forum.com/attachment/5009/dice.rb
>
I've added comments to your code pointing to areas of concern:

puts "How many dice do you want to roll?"
roll = gets.chomp
num_rolls = roll # Why are you assigning to num_rolls here? You never
use this variable!
y = 0 # "y" is a bad name for a variable, generally. What is this
variable for? Why is it 0?
x = y.to_i + 1 # What is "x" for? Why are you calling to_i on
something you just assigned an integer value, so you should know you
don't need this?
while x <= roll.to_i # since you never assign to x, if it is ever
true, it will always be true and you'll never escape from the loop.
puts "Roll " + x.to_s + ": " + rand(max=6).to_s # you are assigning
6 to max -- a variable you never use anywhere else -- and then
immediately passing that to rand. Why?
end

On Tue, Sep 7, 2010 at 8:01 AM, Hd Pwnz0r
<> wrote:
>puts "How many dice do you want to roll?"
>roll = gets.chomp
>num_rolls = roll

num_rolls = gets.to_i

>y = 0
>x = y.to_i + 1

x = 1

>while x <= roll.to_i

while x <= num_rolls

>puts "Roll " + x.to_s + ": " + rand(max=6).to_s

puts "Roll #{x} : #{rand(max=6)+1}"
x += 1

>end
>
> Also, is there a way for me to add one to the rand function so it won't
> get a zero?

cmon, a computer cannot add

revised code below.

DICE_SIDES=6
num_rolls = gets.to_i
x=1
while x <= num_rolls
puts "Roll #{x} : #{rand(DICE_SIDES)+1}"
x+=1
end

=>
Roll 1 : 3
Roll 2 : 1
Roll 3 : 6
Roll 4 : 2
Roll 5 : 3

Welcome to Ruby. Pls do not stop programming!
best regards -botp

David A. Black wrote:
> Hi --
>
> On Tue, 7 Sep 2010, Phlip wrote:
>
>>> get a zero?
>> while x <= roll.to_i
>> puts "Roll " + x.to_s + ": " + rand(max=6).to_s
>> end
>>
>> Take out the gets.chomp:
>>
>> roll = '12' # gets.chomp
>>
>> that lets you work on the loop without entering over and over again.
>
> That changes the behavior of the program pretty significantly, though.
>
>> then either fix your while loop by incrementing: x += 1
>>
>> or use an each loop (which is truly the Ruby way):
>>
>> (0...roll.to_i).each do |x|
>> puts 'etc'
>> end
>
> I'd be inclined to use #times:
>
> print "How many dice do you want to roll? "
> num_rolls = gets.to_i
> num_rolls.times do |n|
> puts "Roll #{n+1}: #{rand(6) + 1}"
> end
>
>
> David
>
> --
> David A. Black, Senior Developer, Cyrus Innovation Inc.
>
> The Ruby training with Black/Brown/McAnally
> Compleat Philadelphia, PA, October 1-2, 2010
> Rubyist http://www.compleatrubyist.com

Hi,

I have made a small change, but both will returns the same result..

By adding the min value to the rand(max-min), we can get random number
bw the range(min,max).

print "How many dice do you want to roll? "
num_rolls = gets.to_i
num_rolls.times do |n|
puts "Roll #{n+1}: #{1 + rand(6-1)}"
end

Thanks,
Vaddi
--
Posted via http://www.ruby-forum.com/.

Vadivelan Vaddi wrote:
> By adding the min value to the rand(max-min), we can get random number
> bw the range(min,max).
>
> print "How many dice do you want to roll? "
> num_rolls = gets.to_i
> num_rolls.times do |n|
> puts "Roll #{n+1}: #{1 + rand(6-1)}"
> end

That's a five-sided die. rand(5) gives a number between 0 and 4
inclusive.
--
Posted via http://www.ruby-forum.com/.

[Note: parts of this message were removed to make it a legal post.]

Thanks Brian for pointed out this. Yes it will returns the value bw 0 and 4
suits for 5-sided die.

We can use this

puts "Roll #{n+1}: #{1 + rand(7-1)}"

This way we can get the values between 0 to 6 as final result.


On Tue, Sep 7, 2010 at 1:22 PM, Brian Candler <> wrote:

> Vadivelan Vaddi wrote:
> > By adding the min value to the rand(max-min), we can get random number
> > bw the range(min,max).
> >
> > print "How many dice do you want to roll? "
> > num_rolls = gets.to_i
> > num_rolls.times do |n|
> > puts "Roll #{n+1}: #{1 + rand(6-1)}"
> > end
>
> That's a five-sided die. rand(5) gives a number between 0 and 4
> inclusive.
> --
> Posted via http://www.ruby-forum.com/.
>
>


--
regards,
vadivelan

[Note: parts of this message were removed to make it a legal post.]

On Tue, Sep 7, 2010 at 4:03 AM, vadivelan K <> wrote:

> Thanks Brian for pointed out this. Yes it will returns the value bw 0 and 4
> suits for 5-sided die.
>
> We can use this
>
> puts "Roll #{n+1}: #{1 + rand(7-1)}"
>
> This way we can get the values between 0 to 6 as final result.
>
>
>

You will get values 1 through 6 (Isn't that why you added the 1?) Also,
seven minus one is six, so why the superfluous math?

(0..1000).map { 1 + rand(6) }.uniq.sort # => [1, 2, 3, 4, 5, 6]