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Any ideas on how to replace a verticle white space?

for example

tetetetetetetete
tetetettetetetete



rererererererere
rerererererererr


such that you end up with

tetetetetetetettete
etetetetetetetetete

rererererererererer
erererererererereer


Thank you
--
Posted via http://www.ruby-forum.com/.

puts s.gsub(/\r\n(\r\n)+/,"\r\n\r\n")

Just adjust the number of \r\n

p.s. have a look mainly at (\r\n)+ : a serie of one or more \r\n


2009/7/17 George George <>

> Any ideas on how to replace a verticle white space?
>
> for example
>
> tetetetetetetete
> tetetettetetetete
>
>
>
> rererererererere
> rerererererererr
>
>
> such that you end up with
>
> tetetetetetetettete
> etetetetetetetetete
>
> rererererererererer
> erererererererereer
>
>
> Thank you
> --
> Posted via http://www.ruby-forum.com/.
>
>


--=20
-- Mirko Viviani --
GPG-PGP Public Key: 0xE4E8FAB1
Fingerprint: 14D3 A373 E926 7737 DF32 502B A4C4 1CE2 E4E8 FAB1
***********************************************
"=93Machines take me by surprise with great frequency.=94 A. Turing

Well... I just tried out with \r\n.... neverthless the solution is the same


2009/7/17 Glenn Jackman <>

> At 2009-07-17 08:11AM, "Mirko Viviani" wrote:
> > 2009/7/17 George George <>
> > > Any ideas on how to replace a verticle white space?
> [...]
> > puts s.gsub(/\r\n(\r\n)+/,"\r\n\r\n")
>
> I would write:
> s.gsub(/((?:\r?\n){2})(?:\r?\n)*/, '\1')
>
> In Ruby, are newlines represented just as "\n" regardless of your
> platform?
>
> --
> Glenn Jackman
> Write a wise saying and your name will live forever. -- Anonymous
>
>


--=20
-- Mirko Viviani --
GPG-PGP Public Key: 0xE4E8FAB1
Fingerprint: 14D3 A373 E926 7737 DF32 502B A4C4 1CE2 E4E8 FAB1
***********************************************
"=93Machines take me by surprise with great frequency.=94 A. Turing

Hi,
Thanks you for the replies. Both approaches did not seem to achieve what
i envisaged. Is because of reading the input as a string? rather than as
a file?

Maybe to rephrase what i really wanted was to be able to delete the
repeated lines and only remain with a single empty line.
meaning if a file had the lines;


tetetetetetetete
tetetettetetetete



rererererererere
rerererererererr

remove the empty lines leaving only a single one

tetetetetetetete
tetetettetetetete

rererererererere
rerererererererr

Thank you
George
--
Posted via http://www.ruby-forum.com/.

On Thu, Jul 23, 2009 at 8:12 AM, George George<> wrote:
> Thanks you for the replies. Both approaches did not seem to achieve what
> i envisaged. Is because of reading the input as a string? rather than as
> a file?
>
> Maybe to rephrase what i really wanted was to be able to delete the
> repeated lines and only remain with a single empty line.
> meaning if a file had the lines;
>
> tetetetetetetete
> tetetettetetetete
>
>
>
> rererererererere
> rerererererererr
>
> remove the empty lines leaving only a single one
>
> tetetetetetetete
> tetetettetetetete
>
> rererererererere
> rerererererererr

Do you have a more specific test case (with code) that is failing?
Reading from a file and using Glenn Jackman's gsub, seems to produce
your desired output:

> cat z
tetetetetetetete
tetetettetetetete



rererererererere
rerererererererr
> ruby -ve 'puts File.new("z").read.gsub(/((?:\r?\n){2})(?:\r?\n)*/, "\\1")'
ruby 1.8.6 (2007-09-24 patchlevel 111) [i386-linux]
tetetetetetetete
tetetettetetetete

rererererererere
rerererererererr
> unix2dos z
unix2dos: converting file z to DOS format ...
> ruby -ve 'puts File.new("z").read.gsub(/((?:\r?\n){2})(?:\r?\n)*/, "\\1")'
ruby 1.8.6 (2007-09-24 patchlevel 111) [i386-linux]
tetetetetetetete
tetetettetetetete

rererererererere
rerererererererr