«

s = "1234" [0..1]
p s #> "12"
p s.to_i #> 12
s = s[1]
p s #> 50
p s.to_i #> 50

I can see the reason for this happening, but I don't want it to happen.

So how do I make it return 2 instead of 50?
--
Posted via http://www.ruby-forum.com/.

On Sat, Jun 27, 2009 at 05:55:20AM +0900, Peter Wu wrote:
> s = "1234" [0..1]
> p s #> "12"
> p s.to_i #> 12
> s = s[1]
> p s #> 50
> p s.to_i #> 50
>
> I can see the reason for this happening, but I don't want it to happen.
>
> So how do I make it return 2 instead of 50?

"1234".split('')[1].to_i # => 2

--
Aaron Patterson
http://tenderlovemaking.com/

Peter Wu wrote:
> s = "1234" [0..1]
> p s #> "12"
> p s.to_i #> 12
> s = s[1]
> p s #> 50
> p s.to_i #> 50
>
> I can see the reason for this happening, but I don't want it to happen.
>
> So how do I make it return 2 instead of 50?

s[1,1]
s[1..1]

--
vjoel : Joel VanderWerf : path berkeley edu : 510 665 3407

Thanks, guys.

--
Posted via http://www.ruby-forum.com/.

Hi,

Am Samstag, 27. Jun 2009, 05:55:20 +0900 schrieb Peter Wu:
> s = "1234" [0..1]
> s = s[1]
> p s #> 50
>
> I can see the reason for this happening, but I don't want it to happen.

The answer has already been given.

As far as I know Ruby 1.9 returns "2".

There's another [] operator that's not well known:

16[4] #=> 1 (the 4th bit is 1)

Bertram


--
Bertram Scharpf
Stuttgart, Deutschland/Germany
http://www.bertram-scharpf.de

One of Ruby's problems is that it invites clever solutions, which are
computationally costly and create undue amounts of garbage.

How about

?> "1234"[1].chr
=> "2"
>>

Cheers,

Bob Schaaf


On Jun 26, 2009, at 4:55 PM, Peter Wu wrote:

> s = "1234" [0..1]
> p s #> "12"
> p s.to_i #> 12
> s = s[1]
> p s #> 50
> p s.to_i #> 50
>
> I can see the reason for this happening, but I don't want it to
> happen.
>
> So how do I make it return 2 instead of 50?
> --
> Posted via http://www.ruby-forum.com/.
>

Hi --

On Sat, 27 Jun 2009, Peter Wu wrote:

> s = "1234" [0..1]
> p s #> "12"
> p s.to_i #> 12
> s = s[1]
> p s #> 50
> p s.to_i #> 50
>
> I can see the reason for this happening, but I don't want it to happen.
>
> So how do I make it return 2 instead of 50?

Addendum to other answers:

In 1.9 it returns the character rather than the character code.


David

--
David A. Black / Ruby Power and Light, LLC
Ruby/Rails consulting & training: http://www.rubypal.com
Now available: The Well-Grounded Rubyist (http://manning.com/black2)
"Ruby 1.9: What You Need To Know" Envycasts with David A. Black
http://www.envycasts.com

Bertram Scharpf wrote:
> There's another [] operator that's not well known:
>
> 16[4] #=> 1 (the 4th bit is 1)

Wow, I've been using ruby for many years but there's
always something new to learn isn't it? Thanks.

Daniel

Peter Wu-5 wrote:
>
> s = "1234" [0..1]
> p s #> "12"
> p s.to_i #> 12
> s = s[1]
> p s #> 50
> p s.to_i #> 50
>
> I can see the reason for this happening, but I don't want it to happen.
>
> So how do I make it return 2 instead of 50?
>
>
p s[1].chr.to_i #=> 2



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