With Ruby 1.9:
def find_square_sides(horiz_segments)
squares = Array.new
horiz_segments.combination(2) do side, candidate
if (...whatever...)
squares << Square.new(side, candidate)
end
end
end
On Feb 16, 2008 6:49 AM, Ruhe <(EMail Removed)> wrote:
> I have array of horizontal segments and I need to find which of them
> may be sides of a box, so I implemented this method:
>
> def find_square_sides(horiz_segments)
> squares = Array.new
> horiz_segments.each_with_index do side, i
> horiz_segments[(i+1)..(horiz_segments.size  1)].each do 
> condidate
> if(## here goes longlong check ##)
> squares << Square.new(side, condidate)
> end
> end
> end
> squares
> end
>
>
> Knowing the beauty of Ruby, I hope that there is a better solution. I
> guess that double iterating isn't the best.
>
>
