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Heres the code. Why does it miss out the "a" character?
------------------------------------------
"This is a test".scan(/\w\w/) {|x| puts x}
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Thanks
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Posted via http://www.ruby-forum.com/.

Alle gioved=C3=AC 3 gennaio 2008, Sam Phoneix ha scritto:
> Heres the code. Why does it miss out the "a" character?
> ------------------------------------------
> "This is a test".scan(/\w\w/) {|x| puts x}
> ------------------------------------------
> Thanks

I guess because the space before the 'a' is not a word character, so ' a'=20
can't match /\w\w/.

Stefano

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On Jan 3, 2008, at 3:23 PM, Sam Phoneix wrote:

> "This is a test".scan(/\w\w/) {|x| puts x}

your regex mataches 2 letter word characters. "a" is only one.

David Morton
Maia Mailguard http://www.maiamailguard.com




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On 3-Jan-08, at 4:23 PM, Sam Phoneix wrote:

> Heres the code. Why does it miss out the "a" character?
> ------------------------------------------
> "This is a test".scan(/\w\w/) {|x| puts x}
> ------------------------------------------
> Thanks
> --
> Posted via http://www.ruby-forum.com/.


Have you researched what the \w matches in a regular expression, and
considered how many of them there are in the argument to scan?

Mike

--

Mike Stok <>
http://www.stok.ca/~mike/

The "`Stok' disclaimers" apply.

Alle gioved=C3=AC 3 gennaio 2008, Stefano Crocco ha scritto:
> Alle gioved=C3=AC 3 gennaio 2008, Sam Phoneix ha scritto:
> > Heres the code. Why does it miss out the "a" character?
> > ------------------------------------------
> > "This is a test".scan(/\w\w/) {|x| puts x}
> > ------------------------------------------
> > Thanks
>
> I guess because the space before the 'a' is not a word character, so ' a'
> can't match /\w\w/.
>
> Stefano

Actually, the situation is a little more complex than I first thought, beca=
use=20
there are other characters near spaces which are included in the result. Th=
e=20
difference comes from the fact that 'a' has a space before and a space afte=
r=20
it. The character 'i' of 'it', instead, is printed because ' i' doesn't=20
match, but 'it' does. With the 'a', there is no matching: neither ' a'=20
nor 'a ' match. The same happens for each word containing an odd number of=
=20
characters. For instance, replacing 'is' with 'isx', you don't get the 'x' =
in=20
the output.

Stefano

David Morton wrote:
> -----BEGIN PGP SIGNED MESSAGE-----
> Hash: SHA1
> your regex mataches 2 letter word characters. "a" is only one.
> -----BEGIN PGP SIGNATURE-----
> Version: GnuPG v1.4.7 (Darwin)
>
> iD8DBQFHfVNzUy30ODPkzl0RAucoAJ45N5rkzbbuMGr3jHAiF1 NAwfPLrgCfeYo0
> pDib5SU+hWuIJfKirdd9G6s=
> =VpNa
> -----END PGP SIGNATURE-----

Thanks

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Posted via http://www.ruby-forum.com/.