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Hello,

Given the following partially specialized template, what would be the
syntax of my_func() definition (out of class)?


tempate<typename T, class Enable = void>
{};

template<typename T>
struct my_class<some_wrapper<T>, typename
enable_if<some_cond<some_wrapper<T> > >::type>
{
my_func();
};


Thanks!

> tempate<typename T, class Enable = void>
> {};

Sorry, I meant:

template<typename T, class Enable = void>
struct my_class
{};

Sorry for the noise. For the above trivial example, the
straightforward syntax seems to compile well:

template<typename T>
my_class<some_wrapper<T>, typename enable_if<some_cond<some_wrapper<T>
> >::type>::my_func()
{}

I just overly simplified my real code, where I had some syntax error.