«

Now, suppose that in

--8<---------------cut here---------------start------------->8---
class X
private:
ostream& out;
Other obj;
--8<---------------cut here---------------end--------------->8---

But object has a constructor that takes "out" as a parameter, which in
this step is of course not initialized.

How can I solve it? With a pointer maybe (also a reference would have
the same problem)?

Or maybe this should not happen in general?

On 10/27/10 10:13 PM, Andrea Crotti wrote:
> Now, suppose that in
>
> --8<---------------cut here---------------start------------->8---
> class X
> private:
> ostream& out;
> Other obj;
> --8<---------------cut here---------------end--------------->8---
>
> But object has a constructor that takes "out" as a parameter, which in
> this step is of course not initialized.
>
> How can I solve it? With a pointer maybe (also a reference would have
> the same problem)?
>
> Or maybe this should not happen in general?

Your questions doesn't make a lot of sense, why don't you post real code?

If a reference member must be initialised in constructors.

--
Ian Collins

Why not to define op<< for 'Other' class instead of passing a
reference to 'ostream' in constructor?
In this case your 'X' class can control how the instance of 'Other' is
printed.

References must be initialized in initializer list, so your X class
also has to define a constructor that takes 'ostream':

class Obj
{
ostream& out;
public:
Obj(ostream& out_) : out(out_) { out << "Obj::Obj" << endl; }
};

class X
{
ostream& out;
Obj o;
public:
X(ostream& out_) : out(out_), o(out_) { out << "X::X=" << endl; }
};