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Jason S wrote:

> I'm working on a program and have encountered a bit of an issue with
> getting my program to work correctly. When I print the array in main(),
> the values print out correctly. But when I debug the program to print
> out their values in the calculatesquares(int[][], int. int) function,
> they come out as very large integers. I assume they might be memory
> addresses? Here's the code:
[...]
> int calculatesquares(int squares[][5], int r, int c)
> {
> int valsAcross[5];
> int valsDown[5];
> int valsDiag[2];
[...]

Just a quick guess, but that looks like uninitialized memory. Could you try:

int valsAcross [5] = {0,0,0,0,0};
...


Best

Kai-Uwe Bux

Pete Becker <> wrote:
>> int valsAcross [5] = {0,0,0,0,0};
>
> Or, if you don't like counting all those zeros,
>
> int valsAcross[5] = { 0 };

I think this will work too:

int valsAcross[5] = { };

On 03/10/2010 15:42, Pete Becker wrote:
> On 2010-10-03 03:31:50 -0400, Juha Nieminen said:
>
>> Pete Becker <> wrote:
>>>> int valsAcross [5] = {0,0,0,0,0};
>>>
>>> Or, if you don't like counting all those zeros,
>>>
>>> int valsAcross[5] = { 0 };
>>
>> I think this will work too:
>>
>> int valsAcross[5] = { };
>
> Maybe. But mine is much clearer. <g>
>

Do you find:

template<typename T>
T make()
{
return T();
}

unclear ?
What is the result of make<int>() ?

What about:

template<typename T>
T*
make()
{
return new T[10]();
}

?
What is make<int>()[0] ?

To me
int valsAcross[5] = {};
is just as clear as
int valsAcross[5] = { 0 };

Then again I've seen presentations/read things about C++0x and
value-initialization.