On Thu, 28 Jan 2010 02:17:08 +0000, Whiskers wrote:
> On 20100128, mart <(EMail Removed)> wrote:
>> If one cycles 800M east for 4 mins, then stops for 4 mins, then cycles
>> 800M east for 2 mins, what is their avg velocity? Avg speed would be
>> 160M/Min (1600M/10mins) but since Velocity involves DIRECTION and
>> speed would it be 1600M/6mins?
>
> No.
>
> Average speed = distance divided by time
>
> Average velocity = displacement divided by time
>
> In your example, both are the same as direction doesn't change.
>
> But if that person had cycled 800 metres east in 4 minutes, stoppped for 2
> minutes, then cycled 800 metres /west/ in 4 minutes:
>
> Average speed = 1,600 metres divided by 10 minutes = 160 metres per
> minute.
>
> Average velocity = (800 metres east minus 800 metres west) divided by 10
> minutes = zero.
>
> <http://www.physics247.com/physicshomeworkhelp/speedvelocityacceleration.php>
Thanks, So both avg speed and velocity are the same in my example.
