parse a string (Cadence Allegro Netlist) to dictionary

Hi,

I always use readline(), strip(), split() and so on to parse a string.
Is there some elegant way to parse the following string into a
dictionary {'50MHZ_CLK_SRC' : 'U122.2, R1395.1'}?

NET_NAME
'50MHZ_CLK_SRC'
'@TEST_LIB.TEST(SCH_1):50MHZ_CLK_SRC':
C_SIGNAL='@test_lib.test(sch_1):\50mhz_clk_src\';
NODE_NAME U122 2
'@TEST_LIB.TEST(SCH_1)AGE92_I223@INF_LOGIC.CY230 5(CHIPS)':
'CLK2': CDS_PINID='CLK2';
NODE_NAME R1395 1
'@TEST_LIB.TEST(SCH_1)AGE92_I232@INF_RESISTORS.R ESISTOR(CHIPS)':
'A': CDS_PINID='A';

Thanks,
Leland

Leland

On 11/5/2009 12:02 PM Leland said...
> Hi,
>
> I always use readline(), strip(), split() and so on to parse a string.
> Is there some elegant way to parse the following string into a
> dictionary {'50MHZ_CLK_SRC' : 'U122.2, R1395.1'}?
>
> NET_NAME
> '50MHZ_CLK_SRC'
> '@TEST_LIB.TEST(SCH_1):50MHZ_CLK_SRC':
> C_SIGNAL='@test_lib.test(sch_1):\50mhz_clk_src\';
> NODE_NAME U122 2
> '@TEST_LIB.TEST(SCH_1)AGE92_I223@INF_LOGIC.CY230 5(CHIPS)':
> 'CLK2': CDS_PINID='CLK2';
> NODE_NAME R1395 1
> '@TEST_LIB.TEST(SCH_1)AGE92_I232@INF_RESISTORS.R ESISTOR(CHIPS)':
> 'A': CDS_PINID='A';
>
> Thanks,
> Leland

This does it, but not very elegantly...

mydict = dict( (kk[0].replace("'",""),",".join(kk[1:]))
for kk in [ [ [ jj for jj in ii.split("\n") if jj.strip() ][0]
for ii in txt.split("_NAME")[1:] ] ])

Emile

Emile van Sebille

On 11ÔÂ6ÈÕ, ÉÏÎç4ʱ02·Ö, Leland <lelandp...@gmail.com> wrote:
> Hi,
>
> I always use readline(), strip(), split() and so on to parse a string.
> Is there some elegant way to parse the following string into a
> dictionary {'50MHZ_CLK_SRC' : 'U122.2, R1395.1'}?
>
> NET_NAME
> '50MHZ_CLK_SRC'
> '@TEST_LIB.TEST(SCH_1):50MHZ_CLK_SRC':
> C_SIGNAL='@test_lib.test(sch_1):\50mhz_clk_src\';
> NODE_NAME U122 2
> '@TEST_LIB.TEST(SCH_1)AGE92_I223@INF_LOGIC.CY230 5(CHIPS)':
> 'CLK2': CDS_PINID='CLK2';
> NODE_NAME R1395 1
> '@TEST_LIB.TEST(SCH_1)AGE92_I232@INF_RESISTORS.R ESISTOR(CHIPS)':
> 'A': CDS_PINID='A';
>
> Thanks,
> Leland

not very elegantly too.

x = re.findall("_NAME[\n\s']+((?<=').+(?=')|\w+\s+\w+)", s)
"""
print {x[0]: x[1:]}
>>> {'50MHZ_CLK_SRC': ['U122 2', 'R1395 1']}
"""

metal

On Nov 5, 7:23 pm, metal <metal...@gmail.com> wrote:
> On 11ÔÂ6ÈÕ, ÉÏÎç4ʱ02·Ö, Leland <lelandp...@gmail..com> wrote:
>
>
>
> > Hi,
>
> > I always use readline(), strip(), split() and so on to parse a string.
> > Is there some elegant way to parse the following string into a
> > dictionary {'50MHZ_CLK_SRC' : 'U122.2, R1395.1'}?
>
> > NET_NAME
> > '50MHZ_CLK_SRC'
> > '@TEST_LIB.TEST(SCH_1):50MHZ_CLK_SRC':
> > C_SIGNAL='@test_lib.test(sch_1):\50mhz_clk_src\';
> > NODE_NAME U122 2
> > '@TEST_LIB.TEST(SCH_1)AGE92_I223@INF_LOGIC.CY230 5(CHIPS)':
> > 'CLK2': CDS_PINID='CLK2';
> > NODE_NAME R1395 1
> > '@TEST_LIB.TEST(SCH_1)AGE92_I232@INF_RESISTORS.R ESISTOR(CHIPS)':
> > 'A': CDS_PINID='A';
>
> > Thanks,
> > Leland
>
> not very elegantly too.
>
> x = re.findall("_NAME[\n\s']+((?<=').+(?=')|\w+\s+\w+)", s)
> """
> print {x[0]: x[1:]}>>> {'50MHZ_CLK_SRC': ['U122 2', 'R1395 1']}
>
> """

@metal

Apparently you and I differ considerably on our conceptions of
elegance.

Joel Davis