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Python - Re: How to write replace string for object which will be substituted?[regexp] |
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08-04-2009, 11:55 PM
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#1 |
Re: How to write replace string for object which will be substituted?[regexp]
ryniek90 wrote:
> Hi. > I started learning regexp, and some things goes well, but most of them > still not. > > I've got problem with some regexp. Better post code here: > > " > >>> import re > >>> mail = '\\nname1 [at] mail [dot] com\nname2 [$at$] > mail [$dot$] com\n' > '\\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > com\n' > >>> print mail > > > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > > >>> maail = re.sub('^\n|$\n', '', mail) > >>> print maail > > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > >>> maail = re.sub(' ', '', maail) > >>> print maail > > name1[at]mail[dot]com > name2[$at$]mail[$dot$]com > >>> maail = re.sub('\[at\]|\[\$at\$\]', '@', maail) > >>> print maail > > name1@mail[dot]com > name2@mail[$dot$]com > >>> maail = re.sub('\[dot\]|\[\$dot\$\]', '.', maail) > >>> print maail > > > > >>> #How must i write the replace string to replace all this regexp's > with just ONE command, in string 'mail' ? > >>> maail = re.sub('^\n|$\n| |\[at\]|\[\$at\$\]|\[dot\]|\[\$dot\$\]', > *?*, mail) > " > > How must i write that replace pattern (look at question mark), to maek > that substituion work? I didn't saw anything helpful while reading Re > doc and HowTo (from Python Doc). I tried with 'MatchObject.group()' but > something gone wrong - didn't wrote it right. > Is there more user friendly HowTo for Python Re, than this? > > I'm new to programming an regexp, sorry for inconvenience. > I don't think you can do it in one regex, nor would I want to. Just use the string's replace() method. >>> mail = '\\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' '\\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' >>> print mail name1 [at] mail [dot] com name2 [$at$] mail [$dot$] com >>> maail = mail.strip() name1 [at] mail [dot] com name2 [$at$] mail [$dot$] com >>> maail = maail.replace(' ', '') >>> print maail name1[at]mail[dot]com name2[$at$]mail[$dot$]com >>> maail = maail.replace('[at]', '@').replace('[$at$]', '@') >>> print maail name1@mail[dot]com name2@mail[$dot$]com >>> maail = maail.replace('[dot]', '.').replace('[$dot$]', '.') >>> print maail MRAB |
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08-05-2009, 07:50 AM
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#2 |
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Posts: n/a
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Re: How to write replace string for object which will be substituted?[regexp]
On 5 Sie, 00:55, MRAB <pyt...@mrabarnett.plus.com> wrote:
> ryniek90 wrote: > > Hi. > > I started learning regexp, and some things goes well, but most of them > > still not. > > > I've got problem with some regexp. Better post code here: > > > " > > *>>> import re > > *>>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] > > mail [$dot$] com\n' > > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > > com\n' > > *>>> print mail > > > n...@mail.com > > name1 [at] mail [dot] com > > name2 [$at$] mail [$dot$] com > > > *>>> maail = re.sub('^\n|$\n', '', mail) > > *>>> print maail > > n...@mail.com > > name1 [at] mail [dot] com > > name2 [$at$] mail [$dot$] com > > *>>> maail = re.sub(' ', '', maail) > > *>>> print maail > > n...@mail.com > > name1[at]mail[dot]com > > name2[$at$]mail[$dot$]com > > *>>> maail = re.sub('\[at\]|\[\$at\$\]', '@', maail) > > *>>> print maail > > n...@mail.com > > name1@mail[dot]com > > name2@mail[$dot$]com > > *>>> maail = re.sub('\[dot\]|\[\$dot\$\]', '.', maail) > > *>>> print maail > > n...@mail.com > > na...@mail.com > > na...@mail.com > > *>>> #How must i write the replace string to replace all this regexp's > > with just ONE command, in string 'mail' ? > > *>>> maail = re.sub('^\n|$\n| |\[at\]|\[\$at\$\]|\[dot\]|\[\$dot\$\]', > > *?*, mail) > > " > > > How must i write that replace pattern (look at question mark), to maek > > that substituion work? I didn't saw anything helpful while reading Re > > doc and HowTo (from Python Doc). I tried with 'MatchObject.group()' but > > something gone wrong - didn't wrote it right. > > Is there more user friendly HowTo for Python Re, than this? > > > I'm new to programming an regexp, sorry for inconvenience. > > I don't think you can do it in one regex, nor would I want to. Just use > the string's replace() method. > > *>>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] > mail [$dot$] com\n' > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > com\n' > *>>> print mail > > n...@mail.com > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > > *>>> maail = mail.strip() > n...@mail.com > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > > *>>> maail = maail.replace(' ', '') > *>>> print maail > n...@mail.com > name1[at]mail[dot]com > name2[$at$]mail[$dot$]com > *>>> maail = maail.replace('[at]', '@').replace('[$at$]', '@') > *>>> print maail > n...@mail.com > name1@mail[dot]com > name2@mail[$dot$]com > *>>> maail = maail.replace('[dot]', '.').replace('[$dot$]', '.') > *>>> print maail > n...@mail.com > na...@mail.com > na...@mail.com Too bad, I thought that the almighty re module could do anything, but it failed with this (or maybe re can do what i want, but only few people knows how to force him to that?  ).But with help of MRAB, i choose The 3rd Point of Python's Zen - "Simple is better than complex." " >>> mail = '\\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' '\\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' >>> print mail name1 [at] mail [dot] com name2 [$at$] mail [$dot$] com >>> maail = mail.lstrip().rstrip().replace(' ', '').replace('[dot]', '.')..replace('[$dot$]', '.').replace('[at]', '@').replace('[$at$]', '@') >>> print maail >>> #Did it  " Thanks again ryniek |
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08-05-2009, 07:53 AM
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#3 |
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Posts: n/a
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Re: How to write replace string for object which will be substituted?[regexp]
On 5 Sie, 00:55, MRAB <pyt...@mrabarnett.plus.com> wrote:
> ryniek90 wrote: > > Hi. > > I started learning regexp, and some things goes well, but most of them > > still not. > > > I've got problem with some regexp. Better post code here: > > > " > > *>>> import re > > *>>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] > > mail [$dot$] com\n' > > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > > com\n' > > *>>> print mail > > > n...@mail.com > > name1 [at] mail [dot] com > > name2 [$at$] mail [$dot$] com > > > *>>> maail = re.sub('^\n|$\n', '', mail) > > *>>> print maail > > n...@mail.com > > name1 [at] mail [dot] com > > name2 [$at$] mail [$dot$] com > > *>>> maail = re.sub(' ', '', maail) > > *>>> print maail > > n...@mail.com > > name1[at]mail[dot]com > > name2[$at$]mail[$dot$]com > > *>>> maail = re.sub('\[at\]|\[\$at\$\]', '@', maail) > > *>>> print maail > > n...@mail.com > > name1@mail[dot]com > > name2@mail[$dot$]com > > *>>> maail = re.sub('\[dot\]|\[\$dot\$\]', '.', maail) > > *>>> print maail > > n...@mail.com > > na...@mail.com > > na...@mail.com > > *>>> #How must i write the replace string to replace all this regexp's > > with just ONE command, in string 'mail' ? > > *>>> maail = re.sub('^\n|$\n| |\[at\]|\[\$at\$\]|\[dot\]|\[\$dot\$\]', > > *?*, mail) > > " > > > How must i write that replace pattern (look at question mark), to maek > > that substituion work? I didn't saw anything helpful while reading Re > > doc and HowTo (from Python Doc). I tried with 'MatchObject.group()' but > > something gone wrong - didn't wrote it right. > > Is there more user friendly HowTo for Python Re, than this? > > > I'm new to programming an regexp, sorry for inconvenience. > > I don't think you can do it in one regex, nor would I want to. Just use > the string's replace() method. > > *>>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] > mail [$dot$] com\n' > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > com\n' > *>>> print mail > > n...@mail.com > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > > *>>> maail = mail.strip() > n...@mail.com > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > > *>>> maail = maail.replace(' ', '') > *>>> print maail > n...@mail.com > name1[at]mail[dot]com > name2[$at$]mail[$dot$]com > *>>> maail = maail.replace('[at]', '@').replace('[$at$]', '@') > *>>> print maail > n...@mail.com > name1@mail[dot]com > name2@mail[$dot$]com > *>>> maail = maail.replace('[dot]', '.').replace('[$dot$]', '.') > *>>> print maail > n...@mail.com > na...@mail.com > na...@mail.com Too bad, I thought that the almighty re module could do anything, but it failed with this (or maybe re can do what i want, but only few people knows how to force him to that? ).But with help of MRAB, i choose The 3rd Point of Python's Zen - "Simple is better than complex." " >>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' >>> print mail n...@mail.com name1 [at] mail [dot] com name2 [$at$] mail [$dot$] com >>> maail = mail.lstrip().rstrip().replace(' ', '').replace('[dot]', '.')..replace('[$dot$]', '.').replace('[at]', '@').replace('[$at$]', '@') >>> print maail n...@mail.com na...@mail.com na...@mail.com >>> #Did it " Thanks again ryniek |
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08-05-2009, 12:40 PM
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#4 |
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Posts: n/a
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Re: How to write replace string for object which will be substituted?[regexp]
On 5 Aug, 07:53, ryniek <rynie...@gmail.com> wrote:
> On 5 Sie, 00:55, MRAB <pyt...@mrabarnett.plus.com> wrote: > > > > > ryniek90 wrote: > > > Hi. > > > I started learning regexp, and some things goes well, but most of them > > > still not. > > > > I've got problem with some regexp. Better post code here: > > > > " > > > *>>> import re > > > *>>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] > > > mail [$dot$] com\n' > > > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > > > com\n' > > > *>>> print mail > > > > n...@mail.com > > > name1 [at] mail [dot] com > > > name2 [$at$] mail [$dot$] com > > > > *>>> maail = re.sub('^\n|$\n', '', mail) > > > *>>> print maail > > > n...@mail.com > > > name1 [at] mail [dot] com > > > name2 [$at$] mail [$dot$] com > > > *>>> maail = re.sub(' ', '', maail) > > > *>>> print maail > > > n...@mail.com > > > name1[at]mail[dot]com > > > name2[$at$]mail[$dot$]com > > > *>>> maail = re.sub('\[at\]|\[\$at\$\]', '@', maail) > > > *>>> print maail > > > n...@mail.com > > > name1@mail[dot]com > > > name2@mail[$dot$]com > > > *>>> maail = re.sub('\[dot\]|\[\$dot\$\]', '.', maail) > > > *>>> print maail > > > n...@mail.com > > > na...@mail.com > > > na...@mail.com > > > *>>> #How must i write the replace string to replace all this regexp's > > > with just ONE command, in string 'mail' ? > > > *>>> maail = re.sub('^\n|$\n| |\[at\]|\[\$at\$\]|\[dot\]|\[\$dot\$\]', > > > *?*, mail) > > > " > > > > How must i write that replace pattern (look at question mark), to maek > > > that substituion work? I didn't saw anything helpful while reading Re > > > doc and HowTo (from Python Doc). I tried with 'MatchObject.group()' but > > > something gone wrong - didn't wrote it right. > > > Is there more user friendly HowTo for Python Re, than this? > > > > I'm new to programming an regexp, sorry for inconvenience. > > > I don't think you can do it in one regex, nor would I want to. Just use > > the string's replace() method. > > > *>>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] > > mail [$dot$] com\n' > > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > > com\n' > > *>>> print mail > > > n...@mail.com > > name1 [at] mail [dot] com > > name2 [$at$] mail [$dot$] com > > > *>>> maail = mail.strip() > > n...@mail.com > > name1 [at] mail [dot] com > > name2 [$at$] mail [$dot$] com > > > *>>> maail = maail.replace(' ', '') > > *>>> print maail > > n...@mail.com > > name1[at]mail[dot]com > > name2[$at$]mail[$dot$]com > > *>>> maail = maail.replace('[at]', '@').replace('[$at$]', '@') > > *>>> print maail > > n...@mail.com > > name1@mail[dot]com > > name2@mail[$dot$]com > > *>>> maail = maail.replace('[dot]', '.').replace('[$dot$]', '.') > > *>>> print maail > > n...@mail.com > > na...@mail.com > > na...@mail.com > > Too bad, I thought that the almighty re module could do anything, but > it failed with this (or maybe re can do what i want, but only few > people knows how to force him to that? * ).> But with help of MRAB, i choose The 3rd Point of Python's Zen - > "Simple is better than complex." > > " > > >>> mail = '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] com\n' > > '\nn...@mail.com\nname1 [at] mail [dot] com\nname2 [$at$] mail [$dot$] > com\n' > > >>> print mail > > n...@mail.com > name1 [at] mail [dot] com > name2 [$at$] mail [$dot$] com > > >>> maail = mail.lstrip().rstrip().replace(' ', '').replace('[dot]', '.').replace('[$dot$]', '.').replace('[at]', '@').replace('[$at$]', '@') > >>> print maail > > n...@mail.com > na...@mail.com > na...@mail.com > > >>> #Did it * > > " > > Thanks again * Short of writing a dedicated function I might be tempted to write this as: EMAIL_REPLACEMENTS = ( ('[at]', '@'), ('[dot]', '.'), ... ) for src, dest in EMAIL_REPLACEMENTS: mail = mail.replace(src, dest) Apart from taste reasons, it keeps the replaces more obvious (and accessible via a variable rather than embedded in the code), enables swapping the order or adding/removing easier. Jon Jon Clements |
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