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Consider the following wsgi app:

def application(env, start_response):
start_response('200 OK',[('Content-type','text/plain')])
yield "hello"
x=1/0
yield "world"

The result of this is that the web browser displays "hello" and an error
message ends up in the web log. But there is no other indication that
an error has occurred.

Is there any way to get WSGI to not silently swallow errors that occur
after start_response has been called?

Thanks,
rg

> Consider the following wsgi app:
>
> def application(env, start_response):
> start_response('200 OK',[('Content-type','text/plain')])
> yield "hello"
> x=1/0
> yield "world"
>
> The result of this is that the web browser displays "hello" and an
> error
> message ends up in the web log. But there is no other indication that
> an error has occurred.
>
> Is there any way to get WSGI to not silently swallow errors that occur
> after start_response has been called?

yes, you can wrap your app in a WebError middleware
http://pypi.python.org/pypi/WebError

from weberror.evalexception import EvalException
application = EvalException(application)


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дамјан ( http://softver.org.mk/damjan/ )

In theory, there is no difference between theory and practice.
But, in practice, there is.