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hello,

i have two vectors and i am combining them into third one:
std::vector<int> orig, result;
std::vector<size_t> perm; // permutations

but i cannot compile following line:
std::transform(perm.begin(), perm.end(), result.begin(), orig[_1]);

because compiler seems to have trouble selecting among:
reindex.cpp:43: error: no match for 'operator[]' in 'orig[_1]'
stl_vector.h:462: candidates are:
_Alloc::reference std::vector<..>:perator[](size_t)
stl_vector.h:476:
_Alloc::const_reference std::vector<..>:perator[](size_t) const

i've tried another form that works
std::transform(perm.begin(), perm.end(), result.begin(),
*(&orig[0]+_1));

can you please help me understand what is going on?

many thanks in advance,
mojmir

mojmir wrote:

> hello,
>
> i have two vectors and i am combining them into third one:
> std::vector<int> orig, result;
> std::vector<size_t> perm; // permutations
>
> but i cannot compile following line:
> std::transform(perm.begin(), perm.end(), result.begin(), orig[_1]);
>
> because compiler seems to have trouble selecting among:
> reindex.cpp:43: error: no match for 'operator[]' in 'orig[_1]'
> stl_vector.h:462: candidates are:
> _Alloc::reference std::vector<..>:perator[](size_t)
> stl_vector.h:476:
> _Alloc::const_reference std::vector<..>:perator[](size_t) const
>
> i've tried another form that works
> std::transform(perm.begin(), perm.end(), result.begin(),
> *(&orig[0]+_1));
>
> can you please help me understand what is going on?

The problem is caused by the language rule that operator[] must be a member
function. In order to turn an expression involving operator[] into a lambda
expression, the left hand operand needs to be "lambdafied" first. Try:

std::transform(perm.begin(), perm.end(), result.begin(), var(orig)[_1]);


Best

Kai-Uwe Bux