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>>> list(itertools.dropwhile(lambda x: x<5,range(10)))
[5, 6, 7, 8, 9]

Why doesn't this work?
>>> list(itertools.dropwhile(lambda x: 2<x<5,range(10)))
[0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

Thanks,

Raj

--
"For him who has conquered the mind, the mind is the best of friends;
but for one who has failed to do so, his very mind will be the
greatest enemy."

Rajanikanth

On Sat, 23 Aug 2008 14:54:09 -0700, Rajanikanth Jammalamadaka wrote:

>>>> list(itertools.dropwhile(lambda x: x<5,range(10)))
> [5, 6, 7, 8, 9]
>
> Why doesn't this work?
>>>> list(itertools.dropwhile(lambda x: 2<x<5,range(10)))
> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]

It *does* work. `dropwhile()` drops as long as the callable returns a
true value and then it stops dropping. First value is 0 and
``2 < 0 < 5`` is `False` so nothing is dropped.

What have you expected?

Ciao,
Marc 'BlackJack' Rintsch

Thanks for the explanations.

Regards,

Raj

On Sat, Aug 23, 2008 at 3:41 PM, Scott David Daniels
<> wrote:
> Rajanikanth Jammalamadaka wrote:
>>>>>
>>>>> list(itertools.dropwhile(lambda x: x<5,range(10)))
>>
>> [5, 6, 7, 8, 9]
>>
>> Why doesn't this work?
>>>>>
>>>>> list(itertools.dropwhile(lambda x: 2<x<5,range(10)))
>>
>> [0, 1, 2, 3, 4, 5, 6, 7, 8, 9]
>
> Because it drops _while_ the condition is True (which it is for
> the first 0 entries in the sequence). What you want is:
>
> list(x for x in range(10) if 2 < x < 5)
>
> Note that:
> list(itertools.dropwhile(lambda x: x<5, range(10)+range(10)))
> is [5, 6, 7, 8, 9, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9],
> not [5, 6, 7, 8, 9, 5, 6, 7, 8, 9].
>
> --Scott David Daniels
> Scott.Daniels.Acm.Org
> --
> http://mail.python.org/mailman/listinfo/python-list
>



--
"For him who has conquered the mind, the mind is the best of friends;
but for one who has failed to do so, his very mind will be the
greatest enemy."

Rajanikanth