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Apparently something like this is not currently possible:

template<typename T>
typedef bool(*VectComp)(const std::vector<T>&, const std::vector<T>&);

void foo(VectComp<int>);

template<typename T>
void bar(VectComp<T>);

Will this be possible in the next C++ standard?

Juha Nieminen a écrit :
> Apparently something like this is not currently possible:
>
> template<typename T>
> typedef bool(*VectComp)(const std::vector<T>&, const std::vector<T>&);

No. template oftypedef are not allowed.
Current usage is:

template<typename T>
struct VectComp
{
typedef bool(*type)(const std::vector<T>&, const std::vector<T>&);
};


>
> void foo(VectComp<int>);

void foo(VectComp<int>::type);

>
> template<typename T>
> void bar(VectComp<T>);

template<typename T>
void bar(typename VectComp<T>::type);

>
> Will this be possible in the next C++ standard?

AFAIK not under this form, it will use aliasing.
See: http://www.artima.com/cppsource/cpp0x.html

Michael