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It is very easy to see what I am trying to do with this code:

#include <stdio.h>

main(){
char name[200];
printf ("Enter -> ");
fflush (stdout);
fgets (name,200,stdin);
printf("is? ",name);}

I have also tried this with the last line with printf

printf("is? %c",name);

Either way same results. Printf will not print the value of name.

Bill

Bill Cunningham wrote:
> It is very easy to see what I am trying to do with this code:

I'm not finding it easy. Please don't assume everyone
else is as perceptive as you are.

> #include <stdio.h>
>
> main(){
> char name[200];
> printf ("Enter -> ");
> fflush (stdout);
> fgets (name,200,stdin);
> printf("is? ",name);}
>
> I have also tried this with the last line with printf
>
> printf("is? %c",name);
>
> Either way same results. Printf will not print the value of name.

Perhaps you want

printf ("is ? %s", name);

--
Eric Sosman
lid

In article <s9Tdj.35028$NL5.2831@trnddc05>,
Bill Cunningham <> wrote:
> It is very easy to see what I am trying to do with this code:

>#include <stdio.h>

>main(){
> char name[200];
> printf ("Enter -> ");
> fflush (stdout);
> fgets (name,200,stdin);
> printf("is? ",name);}

>I have also tried this with the last line with printf

>printf("is? %c",name);

>Either way same results. Printf will not print the value of name.

printf("is? %s", name);
--
"No one has the right to destroy another person's belief by
demanding empirical evidence." -- Ann Landers

"Bill Cunningham" <> schreef in bericht
news:s9Tdj.35028$NL5.2831@trnddc05...
> It is very easy to see what I am trying to do with this code:
>
> #include <stdio.h>
>
> main(){
> char name[200];
> printf ("Enter -> ");
> fflush (stdout);
> fgets (name,200,stdin);
> printf("is? ",name);}
>
> I have also tried this with the last line with printf
>
> printf("is? %c",name);
>
> Either way same results. Printf will not print the value of name.

Strange, I remember somebody years ago with the same name asking these same
kind of newbie questions.

Here, from 2003
http://groups.google.com/group/comp....34df188f17ad68

complete list:
http://groups.google.com/groups?q=gr...&as_maxy=2007&

a troll whose humour I dont understand or what is this?

Bill Cunningham wrote:

> It is very easy to see what I am trying to do with this code:
>
> #include <stdio.h>
>
> main(){
> char name[200];
> printf ("Enter -> ");
> fflush (stdout);
> fgets (name,200,stdin);
> printf("is? ",name);}
>
> I have also tried this with the last line with printf
>
> printf("is? %c",name);
>
> Either way same results. Printf will not print the value of name.

You've supposedly been learning C for months if not years. What book
are you using that doesn't give the procedure for printing strings with
printf()?





Brian

"Eric Sosman" <> wrote in message
news. ..
> Bill Cunningham wrote:
>> It is very easy to see what I am trying to do with this code:
>
> I'm not finding it easy. Please don't assume everyone
> else is as perceptive as you are.
>
>> #include <stdio.h>
>>
>> main(){
>> char name[200];
>> printf ("Enter -> ");
>> fflush (stdout);
>> fgets (name,200,stdin);
>> printf("is? ",name);}
>>
>> I have also tried this with the last line with printf
>>
>> printf("is? %c",name);
>>
>> Either way same results. Printf will not print the value of name.
>
> Perhaps you want
>
> printf ("is ? %s", name);
>
Yes minor stumbling block.
#include <stdio.h>

main(){
char name[200];
char name2[200];
printf ("Enter -> ");
fflush (stdout);
fgets (name,200,stdin);
printf("is? %s",name);
printf("what you mean? Try again.");
fflush(stdout);
fgets(name2,200,stdin);
if (name==name2) {printf("ok");}
else if (name!=name2){
printf("Sorry try again.");
return main();}
return 0;}

THanks now there seems to be an error with if here somewhere. I will try to
figure it out if not I would appreciate a look over.

Bill

> You've supposedly been learning C for months if not years. What book
> are you using that doesn't give the procedure for printing strings with
> printf()?
>
>
>
>
>
> Brian

I have been away from C for over a year. Now I'm trying to give it a go
again and studying again.

Bill

> THanks now there seems to be an error with if here somewhere. I will try
> to figure it out if not I would appreciate a look over.
>
> Bill

OK I got it. Don't use else here.

Bill

On Sun, 30 Dec 2007 23:14:03 +0000, Bill Cunningham wrote:

> if (name==name2) {printf("ok");}

You can't compare strings with ==
The code above compares the addresses of name and name2, to see if
they're equal (which, obviously, they aren't).

You must use strcmp or one of its fellows.

On Sun, 30 Dec 2007 21:37:04 +0000, Default User wrote:

> You've supposedly been learning C for months if not years.

My recollection is that the OP stated he has learning difficulties.
Provided he doesn't start trolling, I suggest slack is cut.