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Hi everyone,

I wanted to run the following loop,
and enter y everytime (I expected that it will ask
me to enter y for 5 time), but just after 3 times program terminates.
what is the error??


#include <stdio.h>

int main ()
{
char ch;
int j=0;
for (j ; j<5 ; j++)
{
printf("Please enter the input character :\n\n");
scanf("%c", &ch);
printf("You have entered : %c \n\n" , ch);

if (ch == 'y' || ch == 'Y')
printf("HIIIIIIIII \n");
}
return 0;
}

<> wrote in message
news:3fd84ee8-d816-4379-98bc-...
> Hi everyone,
>
> I wanted to run the following loop,
> and enter y everytime (I expected that it will ask
> me to enter y for 5 time), but just after 3 times program terminates.
> what is the error??
>
>
> #include <stdio.h>
>
> int main ()
> {
> char ch;
> int j=0;
> for (j ; j<5 ; j++)
> {
> printf("Please enter the input character :\n\n");
> scanf("%c", &ch);
> printf("You have entered : %c \n\n" , ch);

Change the above line to:

printf("You have entered: %c (decimal %d) \n", ch, (int)ch);

and run it again. Look carefully at the results.

>
> if (ch == 'y' || ch == 'Y')
> printf("HIIIIIIIII \n");
> }
> return 0;
> }

-Mike

Now it gives following output, but it is not the expected output.
I still could not find what the problem is.

Please enter the input character :

y
You have entered: y (decimal 121)
HIIIIIIIII
Please enter the input character :

You have entered:
(decimal 10)
Please enter the input character :

y
You have entered: y (decimal 121)
HIIIIIIIII
Please enter the input character :

You have entered:
(decimal 10)
Please enter the input character :

y
You have entered: y (decimal 121)
HIIIIIIIII




On Dec 5, 1:29 am, "Mike Wahler" <mkwah...@mkwahler.net> wrote:
> <j.smit...@googlemail.com> wrote in message
>
> news:3fd84ee8-d816-4379-98bc-...
>
>
>
> > Hi everyone,
>
> > I wanted to run the following loop,
> > and enter y everytime (I expected that it will ask
> > me to enter y for 5 time), but just after 3 times program terminates.
> > what is the error??
>
> > #include <stdio.h>
>
> > int main ()
> > {
> > char ch;
> > int j=0;
> > for (j ; j<5 ; j++)
> > {
> > printf("Please enter the input character :\n\n");
> > scanf("%c", &ch);
> > printf("You have entered : %c \n\n" , ch);
>
> Change the above line to:
>
> printf("You have entered: %c (decimal %d) \n", ch, (int)ch);
>
> and run it again. Look carefully at the results.
>
>
>
> > if (ch == 'y' || ch == 'Y')
> > printf("HIIIIIIIII \n");
> > }
> > return 0;
> > }
>
> -Mike

"" <> writes:

> Now it gives following output, but it is not the expected output.
> I still could not find what the problem is.

This is question 12.18b of the C FAQ:

http://c-faq.com/stdio/scanfc.html

> Please enter the input character :
>
> y
> You have entered: y (decimal 121)
> HIIIIIIIII
> Please enter the input character :
>
> You have entered:
> (decimal 10)
> Please enter the input character :
<snip similar>

PS. Please snip your replies to include on the parts you are
commenting on.

--
Ben.

On Dec 5, 2:00 am, Ben Bacarisse <ben.use...@bsb.me.uk> wrote:
> "j.smit...@googlemail.com" <j.smit...@googlemail.com> writes:
> > Now it gives following output, but it is not the expected output.
> > I still could not find what the problem is.
>
> This is question 12.18b of the C FAQ:
>
> http://c-faq.com/stdio/scanfc.html
>
> > Please enter the input character :
>
> > y
> > You have entered: y (decimal 121)
> > HIIIIIIIII
> > Please enter the input character :
>
> > You have entered:
> > (decimal 10)
> > Please enter the input character :
>
> <snip similar>
>
> PS. Please snip your replies to include on the parts you are
> commenting on.
>
> --
> Ben.

Hello all,

Still I could not solve the problem mentioned.
Do anyone can tell "if I want to run for loop from 1 to 5, everytime
it ask user to enter a character , and if that
character is same with y, then print "Hello" ".

Thank you.

smith

wrote:

What part of

>> PS. Please snip your replies to include on the parts you are
>> commenting on.

didn't you understand?

> Still I could not solve the problem mentioned.

Then you didn't read the FAQ carefully enough.

> Do anyone can tell "if I want to run for loop from 1 to 5, everytime
> it ask user to enter a character , and if that
> character is same with y, then print "Hello" ".

That's a trivial task, but made much harder by your decision
to use scanf().

Try reading the whole of http://c-faq.com/stdio/index.html - question
12.20 is especially relevant.

Then consider rewriting your code without scanf().