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I've read the documentation for the warnings module, but I'm
still unable to figure out how to disable a warning.

I'd like to disable this warning:

Warning: 'with' will become a reserved keyword in Python 2.6

AFAICT, the following should work. But, it doesn't.

import warnings
warnings.filterwarnings('ignore',".*'with' will become a reserved keyword.*")

What am I doing wrong?

--
Grant Edwards grante Yow! And then we could sit
at on the hoods of cars at
visi.com stop lights!

On Sep 10, 12:34 pm, Grant Edwards <gra...@visi.com> wrote:
> I've read the documentation for the warnings module, but I'm
> still unable to figure out how to disable a warning.
>
> I'd like to disable this warning:
>
> Warning: 'with' will become a reserved keyword in Python 2.6
>
> AFAICT, the following should work. But, it doesn't.
>
> import warnings
> warnings.filterwarnings('ignore',".*'with' will become a reserved keyword.*")
>
> What am I doing wrong?
>


That looks to be a compile-time warning. Refer to a
previous discussion here:

http://groups.google.com/group/comp....604b477ad31ef3

--
Hope this helps,
Steven

On 2007-09-10, <> wrote:

>> I'd like to disable this warning:
>>
>> Warning: 'with' will become a reserved keyword in Python 2.6
>>
>> AFAICT, the following should work. But, it doesn't.
>>
>> import warnings
>> warnings.filterwarnings('ignore',".*'with' will become a reserved keyword.*")
>>
>> What am I doing wrong?
>
> That looks to be a compile-time warning.

Doh! Of course it's a compile-time warning.

> Refer to a previous discussion here:
>
> http://groups.google.com/group/comp....604b477ad31ef3

Thanks.

--
Grant Edwards grante Yow! The Osmonds! You are
at all Osmonds!! Throwing up
visi.com on a freeway at dawn!!!