«

In article <. com>,
Ravi <> wrote:

> int pid = fork();

You want a unix newsgroup for this.

>Can you please explain why exclusion of the *ed statement changes the
>output of the program

And it would be helpful to tell people what the change is. If you want
people to help you, don't make them do unnecessary work.

-- Richard



--
"Consideration shall be given to the need for as many as 32 characters
in some alphabets" - X3.4, 1963.

#include <stdio.h>
main()
{
int pid = fork();
if(pid==0) {
printf("1:the child about to become a zombie.pid = %d",getpid());
} else {
printf("\n0.0arent here. pid = %d",getpid());
getchar(); // inclusion of this line changes the output. why?-----*
pid=fork();
if (pid==0) {
printf("\n2:the child about to become a zombie. pid =
%d",getpid());
} else {
printf("\n0.1arent here. pid = %d",getpid());
printf("\n0.2:now look into process table");
getchar();
}
}
}


Can you please explain why exclusion of the *ed statement changes the
output of the program

On Jun 25, 11:36 am, Ravi <ra.ravi....@gmail.com> wrote:
> #include <stdio.h>
> main()
> {
> int pid = fork();
> if(pid==0) {
> printf("1:the child about to become a zombie.pid = %d",getpid());
> } else {
> printf("\n0.0arent here. pid = %d",getpid());
> getchar(); // inclusion of this line changes the output. why?-----*
> pid=fork();
> if (pid==0) {
> printf("\n2:the child about to become a zombie. pid =
> %d",getpid());
> } else {
> printf("\n0.1arent here. pid = %d",getpid());
> printf("\n0.2:now look into process table");
> getchar();
> }
> }
>
> }
>
> Can you please explain why exclusion of the *ed statement changes the
> output of the program

Sorry, but no, we can't.

First off, you use a function (fork()) that is not part of the C
language. Likely, you got this function from someplace else (my guess
is a Unix system function), and while /you/ may know what it does, we
don't.

Secondly, even if we did know what fork() does (and a great number of
here probably do), we don't know what the output of your program looks
like, in order to explain why a single call to getchar() would change
it.

My suggestion is that you ask your question (with more details) in a
forum that knows about C programming and the fork() function.

Ravi wrote:

> #include <stdio.h>
> main()
> {
> int pid = fork();
> if(pid==0) {
> printf("1:the child about to become a zombie.pid = %d",getpid());
> } else {
> printf("\n0.0arent here. pid = %d",getpid());
> getchar(); // inclusion of this line changes the output. why?-----*
> pid=fork();
> if (pid==0) {
> printf("\n2:the child about to become a zombie. pid =
> %d",getpid());
> } else {
> printf("\n0.1arent here. pid = %d",getpid());
> printf("\n0.2:now look into process table");
> getchar();
> }
> }
> }

Try comp.unix.programmer.

> Can you please explain why exclusion of the *ed statement changes the
> output of the program


When you do, tell them what the outputs are.




Brian