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i have a confusion about pointer to functions.can anybody help me to
overcome my confusion??

c beginner skrev:
> i have a confusion about pointer to functions.can anybody help me to
> overcome my confusion??
>
this may do:
http://publications.gbdirect.co.uk/c..._pointers.html

c beginner said:

> i have a confusion about pointer to functions.can anybody help me to
> overcome my confusion??

What is it that is confusing you about pointers to functions?

--
Richard Heathfield
"Usenet is a strange place" - dmr 29/7/1999
http://www.cpax.org.uk
email: rjh at the above domain, - www.

On Jun 17, 9:13 pm, c beginner <saheb1...@gmail.com> wrote:
> i have a confusion about pointer to functions.can anybody help me to
> overcome my confusion??

function pointer holds address of function that you have specified.
as you call function by pointer.

fp = foo(int,int);
so you can call as
*fp(1,2);

depending on requrement you just assign address of function to
pointer.
it will get executed through function pointer call.

On Mon, 18 Jun 2007 08:39:50 -0000, Sachin <> wrote:

>On Jun 17, 9:13 pm, c beginner <saheb1...@gmail.com> wrote:
>> i have a confusion about pointer to functions.can anybody help me to
>> overcome my confusion??
>
>function pointer holds address of function that you have specified.
>as you call function by pointer.
>
>fp = foo(int,int);
>so you can call as
>*fp(1,2);

Don't anyone take any of this code as legitimate c.

>
>depending on requrement you just assign address of function to
>pointer.
>it will get executed through function pointer call.
>


Remove del for email

Sachin wrote:
> On Jun 17, 9:13 pm, c beginner <saheb1...@gmail.com> wrote:
>> i have a confusion about pointer to functions.can anybody help me to
>> overcome my confusion??
>
> function pointer holds address of function that you have specified.
> as you call function by pointer.
>
> fp = foo(int,int);
> so you can call as
> *fp(1,2);
>
> depending on requrement you just assign address of function to
> pointer.
> it will get executed through function pointer call.
>
>
Not quite like that. Let's define the function foo..

int foo(int a, int b) {
return a + b;
}

Now let's define a pointer to function returning int and taking two int
arguments.

int (*fp)(int, int);

Now initialize fp..

fp = foo;

Now you call it through the pointer with..

int x;
x = fp(1, 2);

--
Joe Wright
"Everything should be made as simple as possible, but not simpler."
--- Albert Einstein ---