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Hello,

I need help writing code that converts a given name like into initials
and surname. For example, if a name is Ricky James, it should do R
James and if the name is Henry William James, that should become H W
James.

I have written a method that converts Ricky James to R James and I
have used StringTokenizer, but I need help if the name has 3 or more
tokens, like the second one.

I know I can use StringTokenizer method hasMoreTokens() but I can't
really make out how the logic works.

My try is pasted below:

code:

void myMethod(String name) {

this.name = name;
StringTokenizer str = new StringTokenizer(name, " ");
int numb = str.countTokens();
String first = str.nextToken();
String second = str.nextToken();
System.out.println("The no. of tokens are - " + numb);
System.out.println("The name is - " + first.charAt(0) + "
" + second);

}



Would really appreciate help with this.
Ros

On May 6, 1:41 am, ros <ros...@gmail.com> wrote:
> Hello,
>
> I need help writing code that converts a given name like into initials
> and surname. For example, if a name is Ricky James, it should do R
> James and if the name is Henry William James, that should become H W
> James.
>
> I have written a method that converts Ricky James to R James and I
> have used StringTokenizer, but I need help if the name has 3 or more
> tokens, like the second one.
>
> I know I can use StringTokenizer method hasMoreTokens() but I can't
> really make out how the logic works.
>
> My try is pasted below:
>
> code:
>
> void myMethod(String name) {
>
> this.name = name;
> StringTokenizer str = new StringTokenizer(name, " ");
> int numb = str.countTokens();
> String first = str.nextToken();
> String second = str.nextToken();
> System.out.println("The no. of tokens are - " + numb);
> System.out.println("The name is - " + first.charAt(0) + "
> " + second);
>
> }
>
> Would really appreciate help with this.
> Ros


check countTokens() every time after you used nextToken() to see if it
returns 1. if it returns 1, you know there is only one token left.

something like this:

StringTokenizer str = new StringTokenizer(name);

while(str.hasMoreTokens()){
if(str.countTokens() > 1)
str.nextToken().charAt(0);
else
str.nextToken();
}

On May 6, 12:22 am, ligerdave <david.c...@gmail.com> wrote:
> On May 6, 1:41 am, ros <ros...@gmail.com> wrote:
>
>
>
> > Hello,
>
> > I need help writing code that converts a given name like into initials
> > and surname. For example, if a name is Ricky James, it should do R
> > James and if the name is Henry William James, that should become H W
> > James.
>
> > I have written a method that converts Ricky James to R James and I
> > have used StringTokenizer, but I need help if the name has 3 or more
> > tokens, like the second one.
>
> > I know I can use StringTokenizer method hasMoreTokens() but I can't
> > really make out how the logic works.
>
> > My try is pasted below:
>
> > code:
>
> > void myMethod(String name) {
>
> > this.name = name;
> > StringTokenizer str = new StringTokenizer(name, " ");
> > int numb = str.countTokens();
> > String first = str.nextToken();
> > String second = str.nextToken();
> > System.out.println("The no. of tokens are - " + numb);
> > System.out.println("The name is - " + first.charAt(0) + "
> > " + second);
>
> > }
>
> > Would really appreciate help with this.
> > Ros
>
> check countTokens() every time after you used nextToken() to see if it
> returns 1. if it returns 1, you know there is only one token left.
>
> something like this:
>
> StringTokenizer str = new StringTokenizer(name);
>
> while(str.hasMoreTokens()){
> if(str.countTokens() > 1)
> str.nextToken().charAt(0);
> else
> str.nextToken();
> }

Thanks for the advice ligerdave. That solved my problem.

Really appreciate your help.

Ros