«

hello,


As part of a procedure I've a number sequences like this:

<Python>
if Print_Info: print Datafile.readline()
else: Datafile.readline()
</Python>

Is there a more compressed way to write such a statement,
especially I dislike the redundancy "Datafile.readline()".

thanks,
Stef Mientki

Stef Mientki schrieb:
> hello,
>
>
> As part of a procedure I've a number sequences like this:
>
> <Python>
> if Print_Info: print Datafile.readline()
> else: Datafile.readline()
> </Python>
>
> Is there a more compressed way to write such a statement,
> especially I dislike the redundancy "Datafile.readline()".

d=Datafile.readline()
if Print_info: print d

It's still two lines, but only has a single call to .readline().

HTH,
Martin

"Stef Mientki" <S.Mientki-> wrote in message
news:2c923$462fb3e0$d443bb3a$. nl...
| if Print_Info: print Datafile.readline()
| else: Datafile.readline()

Since both branches discard the data read, I presume Martin's fix is what
you really want.

| Is there a more compressed way to write such a statement,
| especially I dislike the redundancy "Datafile.readline()".

But for future reference, if you really do need to call a method in
multiple places (or even just multiple times in a loop) you can condense
like so:

dread = Datafile.readline # followed by
....
dread() # as needed

Terry Jan Reedy

On 2007-04-25, Stef Mientki <S.Mientki-> wrote:
> hello,
>
>
> As part of a procedure I've a number sequences like this:
>
><Python>
> if Print_Info: print Datafile.readline()
> else: Datafile.readline()
></Python>
>
> Is there a more compressed way to write such a statement,
> especially I dislike the redundancy "Datafile.readline()".
>
> thanks,
> Stef Mientki

You could consider the following

def Print(arg):
print arg

def Noop(arg):
pass

(Print if Print_Info else Noop) (Datafile.readline())

--
Antoon Pardon

Antoon Pardon wrote:
> On 2007-04-25, Stef Mientki <S.Mientki-> wrote:
>
>> hello,
>>
>>
>> As part of a procedure I've a number sequences like this:
>>
>> <Python>
>> if Print_Info: print Datafile.readline()
>> else: Datafile.readline()
>> </Python>
>>
>> Is there a more compressed way to write such a statement,
>> especially I dislike the redundancy "Datafile.readline()".
>>
>> thanks,
>> Stef Mientki
>>
>
> You could consider the following
>
> def Print(arg):
> print arg
>
> def Noop(arg):
> pass
>
> (Print if Print_Info else Noop) (Datafile.readline())
>
>
thank you all for your answers,
I'll play a little with the suggested solutions.

cheers,
Stef Mientki

On Apr 26, 1:58 am, Antoon Pardon <apar...@forel.vub.ac.be> wrote:
> On 2007-04-25, Stef Mientki <S.Mientki-nos...@mailbox.kun.nl> wrote:
>
> > hello,
>
> > As part of a procedure I've a number sequences like this:
>
> ><Python>
> > if Print_Info: print Datafile.readline()
> > else: Datafile.readline()
> ></Python>
>
> > Is there a more compressed way to write such a statement,
> > especially I dislike the redundancy "Datafile.readline()".
>
> > thanks,
> > Stef Mientki
>
> You could consider the following
>
> def Print(arg):
> print arg
>
> def Noop(arg):
> pass
>

or (untested):

if Print_Info:
def printOrNot(arg):
print arg
else:
def printOrNot(arg):
pass

printOrNot(Datafile.readline())

> (Print if Print_Info else Noop) (Datafile.readline())
>
> --
> Antoon Pardon

> or (untested):
>
> if Print_Info:
> def printOrNot(arg):
> print arg
> else:
> def printOrNot(arg):
> pass
>
> printOrNot(Datafile.readline())
>
>
thanks for the creative solution, and indeed it does work

cheers,
Stef Mientki

On Apr 26, 7:31 am, Dustan <DustanGro...@gmail.com> wrote:
> On Apr 26, 1:58 am, Antoon Pardon <apar...@forel.vub.ac.be> wrote:
>
>
>
>
>
> > On 2007-04-25, Stef Mientki <S.Mientki-nos...@mailbox.kun.nl> wrote:
>
> > > hello,
>
> > > As part of a procedure I've a number sequences like this:
>
> > ><Python>
> > > if Print_Info: print Datafile.readline()
> > > else: Datafile.readline()
> > ></Python>
>
> > > Is there a more compressed way to write such a statement,
> > > especially I dislike the redundancy "Datafile.readline()".
>
> > > thanks,
> > > Stef Mientki
>
> > You could consider the following
>
> > def Print(arg):
> > print arg
>
> > def Noop(arg):
> > pass
>
> or (untested):
>
> if Print_Info:
> def printOrNot(arg):
> print arg
> else:
> def printOrNot(arg):
> pass
>
> printOrNot(Datafile.readline())
>
>
>
> > (Print if Print_Info else Noop) (Datafile.readline())
>
> > --
> > Antoon Pardon- Hide quoted text -
>
> - Show quoted text -- Hide quoted text -
>
> - Show quoted text -

The Enable/Disable decorators on the Python wiki (http://
wiki.python.org/moin/PythonDecoratorLibrary?highlight=%28decorator
%29#head-8298dbf9ac7325d9ef15e7130e676378bbbda572) help you do
something very similar, without having to replicate the function being
enabled/disabled.

@(disabled,enabled)[Print_Info]
def printOrNot(arg):
print arg

-- Paul

Paul McGuire <> wrote:

> The Enable/Disable decorators on the Python wiki (http://
> wiki.python.org/moin/PythonDecoratorLibrary?highlight=%28decorator
> %29#head-8298dbf9ac7325d9ef15e7130e676378bbbda572) help you do
> something very similar, without having to replicate the function being
> enabled/disabled.
>
> @(disabled,enabled)[Print_Info]
> def printOrNot(arg):
> print arg
>

Pardon me for asking, but isn't that a syntax error? Decorator syntax is:

"@" dotted_name ["(" [argument_list [","]] ")"] NEWLINE

and you don't have a dotted_name.

On Apr 27, 9:45 am, Duncan Booth <duncan.bo...@invalid.invalid> wrote:
> Paul McGuire <p...@austin.rr.com> wrote:
> > The Enable/Disable decorators on the Python wiki (http://
> > wiki.python.org/moin/PythonDecoratorLibrary?highlight=%28decorator
> > %29#head-8298dbf9ac7325d9ef15e7130e676378bbbda572) help you do
> > something very similar, without having to replicate the function being
> > enabled/disabled.
>
> > @(disabled,enabled)[Print_Info]
> > def printOrNot(arg):
> > print arg
>
> Pardon me for asking, but isn't that a syntax error? Decorator syntax is:
>
> "@" dotted_name ["(" [argument_list [","]] ")"] NEWLINE
>
> and you don't have a dotted_name.

My bad. The wiki example assigns the appropriate decorator to another
name, and then uses that name, like this:

debugFlag = int(False)
state = (disabled,enabled)[debugFlag] # <-- proper way to do this

@state
def debugPrint(s):
print s

print "here comes some debug output"
debugPrint("xyzzy is the secret word")
print "that was it"


I think early in the decorator syntax discussions, there were some
proposals that decorators could be expressions, but I guess I forgot
which way that was decided. The example in this post does work (and
so does the one on the wiki) .

-- Paul