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Hi,
I have a Java program which polls a directory for incoming files
(zipped and text).
When a new file comes, I read it and post it's outcome.

Here I have some encoding problems. The text files are usually UTF-8,
so I hard-code the encoding to UTF-8:

Code extract:
....
// trying to read the file "myFile"
FileInputStream fi = new FileInputStream(myFile);
InputStreamReader ir = new InputStreamReader(fi, "UTF8"); // hardcoded
UTF-8, how can I do this dynamically?
....

I was expecting the zipped files to be UTF-8 as well, but it turned
out not to be, so I get an:
MalformedInputException at
sun.io.ByteToCharUTF8.convert([BII[CII)I(ByteToCharUTF8

So I have to handle the two separately and it troubles my code.

I guess there's a smart way of doing this.
Hope someone can give me some hint on this!

Regards, Per Magnus

On 17 Apr 2007 09:25:47 -0700, Perma wrote:
> I was expecting the zipped files to be UTF-8 as well, but it turned
> out not to be, so I get an:

> MalformedInputException at
> sun.io.ByteToCharUTF8.convert([BII[CII)I(ByteToCharUTF8
>
> So I have to handle the two separately and it troubles my code.

Character encoding is an attribute that describes how characters are
represented as bytes in *text* files. Classes that are "readers" read
from a stream and apply the specified encoding to obtain the text.
This operation is only meaninful when applied to text files.

Zipped files are binary, not text, so they don't contain characters
and there is no character encoding. To read a zipped file, use an
InputStream (to read raw bytes), or e.g. a ZipInputStream to get the
unzipped contents.

/gordon

--

Perma schrieb:
> I was expecting the zipped files to be UTF-8 as well, but it turned
> out not to be, so I get an:
> MalformedInputException at
> sun.io.ByteToCharUTF8.convert([BII[CII)I(ByteToCharUTF8
>
> So I have to handle the two separately and it troubles my code.
>
> I guess there's a smart way of doing this.
> Hope someone can give me some hint on this!

There is no 100% solution if you have to guess the encoding.
But you can exploit the fact, that input which may be interpreted
as UTF-8-encoded without error, in almost all cases is actually
UTF-8 encoded.


So just try do apply UTF-8, catch the exception or search for
the invalid marker character (defaults to \uFFFD) and apply
an alternate charset on error.



Kai

"Gordon Beaton" <> wrote in message
news:4624f80e$0$24610$...
>
> Zipped files are binary, not text, so they don't contain characters
> and there is no character encoding.

That is, zip files are binary. Zipped files (the files that were processed
to create the zip file) may be binary or text.

"Perma" <> wrote in message
news: oups.com...
> Hi,
> I have a Java program which polls a directory for incoming files
> (zipped and text).
> When a new file comes, I read it and post it's outcome.
>
> Here I have some encoding problems. The text files are usually UTF-8,
> so I hard-code the encoding to UTF-8:
>
> Code extract:
> ...
> // trying to read the file "myFile"
> FileInputStream fi = new FileInputStream(myFile);
> InputStreamReader ir = new InputStreamReader(fi, "UTF8"); // hardcoded
> UTF-8, how can I do this dynamically?
> ...
>
> I was expecting the zipped files to be UTF-8 as well, but it turned
> out not to be, so I get an:
> MalformedInputException at
> sun.io.ByteToCharUTF8.convert([BII[CII)I(ByteToCharUTF8
>
> So I have to handle the two separately and it troubles my code.
>
> I guess there's a smart way of doing this.
> Hope someone can give me some hint on this!

Maybe I'm misunderstanding something, but zip files are NOT text files
encoded via the UTF-8 encoding. In fact, they're not text files at all,
but binary files. Thus the question of "which encoding?" never has a
chance to come up at all.

- Oliver

I am aware of that a zip file is not a text file, but it contains a
text file.
When unzipping the text file, I need to figure out what encoding it
is.

>From the postings above, it sounds to me as if there is no method
which can tell me whether it is "UTF-8" or not, so perhaps the best
solution is to try to read the file as UTF-8, and handling non-UTF-8
files by re-reading them in the Exception handling method.
Example:

InputStreamReader ir
try {
// trying to read as utf-8
ir = new InputStreamReader(fi, "UTF8");
} catch (Exception e {
// couldn't read file as UTF-8, therefore reading it as nont-UTF-8
encoding
ir = new InputStreamReader(fi);
}

Thank you for responses!
And please update if you have some alternative solutions to this.

-Per Magnus

On 18 Apr, 00:09, "Oliver Wong" <o...@castortech.com> wrote:
> "Perma" <kebabkon...@hotmail.com> wrote in message
>
> news: oups.com...
>
>
>
> > Hi,
> > I have a Java program which polls a directory for incoming files
> > (zipped and text).
> > When a new file comes, I read it and post it's outcome.
>
> > Here I have some encoding problems. The text files are usually UTF-8,
> > so I hard-code the encoding to UTF-8:
>
> > Code extract:
> > ...
> > // trying to read the file "myFile"
> > FileInputStream fi = new FileInputStream(myFile);
> > InputStreamReader ir = new InputStreamReader(fi, "UTF8"); // hardcoded
> > UTF-8, how can I do this dynamically?
> > ...
>
> > I was expecting the zipped files to be UTF-8 as well, but it turned
> > out not to be, so I get an:
> > MalformedInputException at
> > sun.io.ByteToCharUTF8.convert([BII[CII)I(ByteToCharUTF8
>
> > So I have to handle the two separately and it troubles my code.
>
> > I guess there's a smart way of doing this.
> > Hope someone can give me some hint on this!
>
> Maybe I'm misunderstanding something, but zip files are NOT text files
> encoded via the UTF-8 encoding. In fact, they're not text files at all,
> but binary files. Thus the question of "which encoding?" never has a
> chance to come up at all.
>
> - Oliver

Perma wrote:
> I am aware of that a zip file is not a text file, but it contains a
> text file. When unzipping the text file, I need to figure out what encoding it
> is.
>
Fire up your ZIP utility and take a good look at the file headers it
lists from the zip archive. What you see there is about all it knows
about compressed files. I don't think it knows or cares what's in the
file apart from what's implied by the filename extension.

I think you'll be better off extracting the file as a bytestream
because I'm 99% certain that's what the zip archiver thought it had
compressed.

Don't forget that ASCII text, Unicode wordprocessor files,
JPEG images and binary executables are all the same to the ZIP archiver.


--
martin@ | Martin Gregorie
gregorie. | Essex, UK
org |

[jitmer@hotmail.com]

Use the below code to read from a text file which are delimited with pipe and | and output the tokens or string


try{

FileReader infile=new FileReader(file);


bufRdr = new BufferedReader(new FileReader(file));
} catch (FileNotFoundException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
String line = null;

int row = 0;int col = 0; //read each line of text file
try {
while((line = bufRdr.readLine()) != null && rowcount<1 ){
StringTokenizer st = new StringTokenizer(line,"|");

while (st.hasMoreTokens()) {

// System.out.println( "NextToken " +st.nextToken());

// valArray[col]=st.nextToken();

System.out.println( "NextToken " +st.nextToken());


//System.out.println( "Columns " +rowcount);
}
}