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VHDL - Signal zaehl cannot be synthesized |
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#1 |
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Hi Guys! I've got a problem with my vhdl code. I am very new at programming in this language and for this reason i am not be able to find the mistake. I tried hard without success. Signal zaehl cannot be synthesized, bad synchronous description. I hope somebody can help me. Furthermore, this project must be programmed at school.
ENTITY zaehler IS PORT ( clock, zuendung, automatik : in std_logic; katnr, rauf, runter ,sperr_ext :in bit; leda, ledb, ledc, ledd, lede, ledf, ledg, dp, ledrauf, ledrunter, ledkatnr, transistor1, transistor2 END zaehler ; ARCHITECTURE number_one OF zaehler IS signal gang : std_logic_vector (2 downto 0); signal zaehl : std_logic_vector (5 downto 0);-- badsynchronous description signal zaehl_sperr : std_logic_vector (6 downto 0); signal zaehl_auto : std_logic_vector (7 downto 0); signal gang_alt : std_logic_vector (2 downto 0); BEGIN PROCESS (clock, zuendung, automatik, katnr, zaehl, zaehl_sperr, zaehl_auto, gang, gang_alt, rauf, runter, sperr_ext) BEGIN transistor1 <= '0'; transistor2 <= '1'; gang <= "001"; zaehl<= "000000"; zaehl_sperr <= "1010101"; zaehl_auto <= "00000000"; Reload6156 |
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#2 |
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Junior Member
Join Date: Mar 2007
Posts: 14
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Remove the signals zaehl, zaehl_sperr, zaehl_auto, gang & gang_alt from the sensitivity list and the problem should be solved. Put only signals that you want your process to trigger on, for instance clock and reset for a synchronous architecture, in the sensitivity list.
The reason you get the error on 'zaehl' is probably because it is the first one in the list. Martin martin.wahlstedt |
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