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I've built some code under Visual Studio C++ (2005) and sizeof(int) is
4 bytes whether the code is built for 32 or 64 bit platforms. (I'm
running on a 64 bit machine.)

I was of the impression that the Ansi spec defines 'int' to be the same
as the native word size of the machine. Am I wrong or is there a
compile flag or manifest that would get sizeof(int) to be 8?

Thanks.

- David

I think you are right. I can't tell you what it is, but most likely a
pre-processor directive.


Tony. . .


"David" <> wrote in message
news: ups.com...
> I've built some code under Visual Studio C++ (2005) and sizeof(int) is
> 4 bytes whether the code is built for 32 or 64 bit platforms. (I'm
> running on a 64 bit machine.)
>
> I was of the impression that the Ansi spec defines 'int' to be the same
> as the native word size of the machine. Am I wrong or is there a
> compile flag or manifest that would get sizeof(int) to be 8?
>
> Thanks.
>
> - David
>

"David" <> skrev i meddelandet
news: ups.com...
> I've built some code under Visual Studio C++ (2005) and sizeof(int)
> is
> 4 bytes whether the code is built for 32 or 64 bit platforms. (I'm
> running on a 64 bit machine.)
>
> I was of the impression that the Ansi spec defines 'int' to be the
> same
> as the native word size of the machine.

For some definition of 'native'.

For x64, a 32 bit int *is* the native size, as it produces the
smallest code size. To use 64 bit operands, the machine code must
include a size override prefix.

> Am I wrong or is there a
> compile flag or manifest that would get sizeof(int) to be 8?

No, there is not.

On some systems, Linux in particular, sizeof(long) might be 8. With MS
C++, sizeof(long)==sizeof(int)==8.


Bo Persson

"Bo Persson" <> skrev i meddelandet
news:OyrjQn%...
>
> "David" <> skrev i meddelandet
> news: ups.com...
>> I've built some code under Visual Studio C++ (2005) and sizeof(int)
>> is
>> 4 bytes whether the code is built for 32 or 64 bit platforms. (I'm
>> running on a 64 bit machine.)
>>
>> I was of the impression that the Ansi spec defines 'int' to be the
>> same
>> as the native word size of the machine.
>
> For some definition of 'native'.
>
> For x64, a 32 bit int *is* the native size, as it produces the
> smallest code size. To use 64 bit operands, the machine code must
> include a size override prefix.
>
>> Am I wrong or is there a
>> compile flag or manifest that would get sizeof(int) to be 8?
>
> No, there is not.
>
> On some systems, Linux in particular, sizeof(long) might be 8. With
> MS C++, sizeof(long)==sizeof(int)==8.
^^^^

****!

It looks kinda like an 8, but is really a 4 (four). Honest!


Bo Persson

The only thing the C and C++ standards define as far as type sizes is
concerned is:

sizeof char <= sizeof short <= sizeof int <= sizeof long

Win64 defines int and long to be 32-bit. Presumably for compatibility
reasons as much as anything else. Be aware that size_t is 64-bit though.
(This is currently causing me a few headaches.)


(Another gotcha to watch out for is NULL still being defined as 0 instead of
0LL. Which is a real problem when you try to pass a NULL pointer to a
varargs function. The caller pushes a 32-bit integer 0, while the callee
tries to retrieve a 64-bit pointer 0. Oh the fun I had with that one...)



"David" <> wrote in message
news: ups.com...
> I've built some code under Visual Studio C++ (2005) and sizeof(int) is
> 4 bytes whether the code is built for 32 or 64 bit platforms. (I'm
> running on a 64 bit machine.)
>
> I was of the impression that the Ansi spec defines 'int' to be the same
> as the native word size of the machine. Am I wrong or is there a
> compile flag or manifest that would get sizeof(int) to be 8?
>
> Thanks.
>
> - David
>

> (Another gotcha to watch out for is NULL still being defined as 0 instead
> of 0LL. Which is a real problem when you try to pass a NULL pointer to a
> varargs function. The caller pushes a 32-bit integer 0, while the callee
> tries to retrieve a 64-bit pointer 0. Oh the fun I had with that one...)

Stop it, you're creeping me out...

[tha_specializt]

Originally Posted by Bo Persson

On some systems, Linux in particular, sizeof(long) might be 8. With MS
C++, sizeof(long)==sizeof(int)==8.

Wow, it appears you dont know what you're talking about ....

msdn.microsoft.com/en-us/library/aa383751%28v=VS.85%29.aspx

Both sizeof(int) and sizeof(long) == 4. Learn to use Google before you post things