Velocity Reviews > MCSE > Calculating max. number of subnets RFC950 or RFC1878

# Calculating max. number of subnets RFC950 or RFC1878

Jeffrey Kusters
Guest
Posts: n/a

 10-04-2003
Does anyone know if Microsoft bases their exams on RFC950
or RFC1878 for calculating the maximum number of possible
subnets (use 2^n-2 or just 2^n).

In other words, does Microsoft allow use of the all 0's
and all 1's subnets???

kindest regards,

Jeffrey Kusters
MCP, MCSA, MCSE, CCNA

A. Vargas
Guest
Posts: n/a

 10-05-2003
For subnetting you should use the equation ((2^n)-2)
becuase all 0's identifies the subnet itself and all 1's

A. Vargas
>-----Original Message-----
>Does anyone know if Microsoft bases their exams on RFC950
>or RFC1878 for calculating the maximum number of possible
>subnets (use 2^n-2 or just 2^n).
>
>In other words, does Microsoft allow use of the all 0's
>and all 1's subnets???
>
>kindest regards,
>
>Jeffrey Kusters
>MCP, MCSA, MCSE, CCNA
>.
>

Andy Foster
Guest
Posts: n/a

 10-05-2003
"Jeffrey Kusters" <(E-Mail Removed)> wrote in message news:<10ac01c38acd\$3f8ba130\$(E-Mail Removed)>...
> Does anyone know if Microsoft bases their exams on RFC950
> or RFC1878 for calculating the maximum number of possible
> subnets (use 2^n-2 or just 2^n).
>
> In other words, does Microsoft allow use of the all 0's
> and all 1's subnets???
>
> kindest regards,
>
> Jeffrey Kusters
> MCP, MCSA, MCSE, CCNA

It *should* be 2^n, but be aware that they may use 2^n-2.
You should not get any questions where you have to chose between them.
If you did, it would almost certainly mention the RFC in question.

HTH

Andy