«

Hi,

If there is operator overloading in both side of the binary operator,
such as: a < b.

Will the a's operator function be called or b?

Thanks.
ABAI

Binary wrote:
> Hi,
>
> If there is operator overloading in both side of the binary operator,
> such as: a < b.
>
> Will the a's operator function be called or b?
>
why not try?

Binary wrote:
> Hi,
>
> If there is operator overloading in both side of the binary operator,
> such as: a < b.
>
Depends on what the operators are. It's possible that there are
no overloads for < that match, a unique best overload (which is the
one that is called), or multiple equally good ones which would be
an error due to the ambiguity.

You need to know what operator < overloads are available and whether
the types of a and b can be converted to what these < operators take.

Binary wrote:

> If there is operator overloading in both side of the binary operator,
> such as: a < b.
> Will the a's operator function be called or b?

Write (or imagine you write) the code as: operator < (a, b)

Then imagine that "operator <" is "somefunctionname"

Then use your knowledge about overloading resolution for functions to
resolve somefunctioname.

--
Salu2