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I have code like this :

void foo(int i, void* p) { .. }


class A
{
public:
A();
~A();

private:
void foobar(int i, char* c);
};



Is there a way for foo to call foobar() ?

Lucy Ludmiller wrote:
> I have code like this :
>
> void foo(int i, void* p) { .. }
>
> class A
> {
> public:
> A();
> ~A();
> private:
> void foobar(int i, char* c);
> };
>
> Is there a way for foo to call foobar() ?

Sure:

void foo(int i, void* p)
{
A a;
a.foobar(i, static_cast<char*>(p));
}

But if your question is, can foo call foobar without an instance of
class A to call it with, the answer is no, unless you change foobar to
be a static member of A.

Best regards,

Tom

Thomas Tutone wrote:
> Lucy Ludmiller wrote:
> > I have code like this :
> >
> > void foo(int i, void* p) { .. }
> >
> > class A
> > {
> > public:
> > A();
> > ~A();
> > private:
> > void foobar(int i, char* c);
> > };
> >
> > Is there a way for foo to call foobar() ?
>
> Sure:
>
> void foo(int i, void* p)
> {
> A a;
> a.foobar(i, static_cast<char*>(p));
> }

.... if class A declares foo as a friend:
class A
{
friend void foo(int i, void* p) ;
//.....
};

HTH
Radu

>
> But if your question is, can foo call foobar without an instance of
> class A to call it with, the answer is no, unless you change foobar to
> be a static member of A.
>

you can declaring
> Best regards,
>
> Tom

Radu wrote:
> Thomas Tutone wrote:
> > Lucy Ludmiller wrote:
> > > I have code like this :
> > >
> > > void foo(int i, void* p) { .. }
> > >
> > > class A
> > > {
> > > public:
> > > A();
> > > ~A();
> > > private:
> > > void foobar(int i, char* c);
> > > };
> > >
> > > Is there a way for foo to call foobar() ?
> >
> > Sure:
> >
> > void foo(int i, void* p)
> > {
> > A a;
> > a.foobar(i, static_cast<char*>(p));
> > }
>
> ... if class A declares foo as a friend:
> class A
> {
> friend void foo(int i, void* p) ;
> //.....
> };

Good point - I missed that foo was private. Thanks for the
clarification.

Best regards,

Tom