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Hi,

Can you please tell me when does the destructor of a static object gets
called?

Thank you.

On 10 Mar 2006 08:08:08 -0800, wrote:

>Hi,
>
>Can you please tell me when does the destructor of a static object gets
>called?
>
>Thank you.

Why do you ask here? It's in your textbook, isn't it?

--
Bob Hairgrove

wrote:
> Can you please tell me when does the destructor of a static object gets
> called?

At some point after 'main' has returned.

V
--
Please remove capital As from my address when replying by mail

Hi!

:
> Can you please tell me when does the destructor of a static object gets
> called?

You mean objects in unnamed namespaces like

#include <iostream>
#include <ostream>

class A {
public:
~A() { std::cout <<"~A"; }
};

namespace {
A a;
}

int main() {
return 0;
}

What do you guess? Did you try out?

Regards,
Matthias

Matthias Kluwe wrote:
> :
>
>>Can you please tell me when does the destructor of a static object gets
>>called?
>
>
> You mean objects in unnamed namespaces [...]

I would guess 'no'. Usually "a static object" means an object with static
_storage_duration_.

V
--
Please remove capital As from my address when replying by mail

A static object is created as the programs starts to run upon
allocation of all global variables... therefore it is destroyed when
all global variables are deallocated (ie. at program exit)

wrote:
> A static object is created as the programs starts to run upon
> allocation of all global variables... therefore it is destroyed when
> all global variables are deallocated (ie. at program exit)

A static object can be declared inside a function, and be never created
if that function is never called. And as a result, such object is never
destroyed. How 'bout that?

V
--
Please remove capital As from my address when replying by mail

are you suggesting the destructor is never called?

Diego Martins wrote:
> are you suggesting the destructor is never called?

Please quote what you are referring to.

He is saying that the object may never be constructed. In that case,
the destructor will not be called, of course.

Ben Pope
--
I'm not just a number. To many, I'm known as a string...