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Wrapping C code into a C++ object

Jonathan Mcdougall
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Ben Pope wrote:
> Jonathan Mcdougall wrote:
> > Ben Pope wrote:
> >> Tom the Canuck wrote:
> >>> What would be the best way to proceed?
> >>> Should I make a pure virtual class and then
> >>> derive from that? I want the base class to have
> >>> functions defined so that I don't have to do the
> >>> work all over again in the derived class. Is this
> >>> not what objects are for?
> >>> Please illuminate on how to do this properly.
> >>> I don't want code, just a pointer on how to
> >>> do the job right.
> >>> Any comments or links will help.
> >>>
> >>> The C code is OpenGL. I just want a class
> >>> to make life easier for future projects.
> >>> If requested, I can send the source code done
> >>> up to now. I do not believe in wasting space, so
> >>> it is not in this post.
> >>
> >>
> >> Just a quick example of wrapping an existing library and RAII:
> >>
> >> // Keep the old library hidden
> >> namespace libraryImpl {
> >> # include "library.h"
> >> }

> >
> > This won't work if the functions were defined in another namespace than
> > libraryImpl (as they probably will). libraryImpl::f() is *not* ::f()!

> Yeah, I did think about this after posting. I've seen the same problem
> when including windows.h.
> Presumably it doesn't matter if you #include from the source file and
> bring everything into the global namespace as it's local to the
> translation unit anyway.

When wrapping a library in a class, it is common to need member objects
defined by that library.

# include "the library"

class Wrapper

LibraryStruct s;

The problem here is that you have no choice but to include the library
header in the wrapper's header, making it visible to users. You could
make "s" a pointer and only declare LibraryStruct,

// don't need that anymore
// # include "the library"

class LibraryStruct;

class Wrapper

LibraryStruct *s;

but that could also mean some problems, for example if another version
of the library changes LibraryStruct to be a typedef of a template
(such as std::string).

The usual solution would be to use the "pimpl" idiom (or the Bridge

// w.h
# include <memory>

class WrapperImpl;

namespace N

class Wrapper

std::auto_ptr<WrapperImpl> impl_;


// w.cpp
# include "w.h"
# include "the library" // clients don't know about it

namespace N

class WrapperImpl
LibraryStruct s;

: impl_(new WrapperImpl)



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