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Hi,
Can any one explain this to me....

"For every quintuple (C1, C2, T, CV1, CV2), where C2 is a class type,
C1 is the same type as C2 or is a
derived class of C2, T is an object type or a function type, and CV1
and CV2 are cvqualifierseqs,
there
exist candidate operator functions of the form
CV12 T& operator>*(
CV1 C1*, CV2 T C2::*);
where CV12 is the union of CV1 and CV2."

Everything is understandble , but for
CV2 T C2::*

what does this mean ?

Help
sandSpiderX

operator is :- as shown above ,

CV12 T& operator->*(CV1 C1*, CV2 T C2::*);

thanks...
sandSpiderX

sandSpiderX schreef:
> Hi,
> Can any one explain this to me....
>
> "For every quintuple (C1, C2, T, CV1, CV2), where C2 is a class type,
> C1 is the same type as C2 or is a
> derived class of C2, T is an object type or a function type, and CV1
> and CV2 are cvqualifierseqs,
> there
> exist candidate operator functions of the form
> CV12 T& operator>*(
> CV1 C1*, CV2 T C2::*);
> where CV12 is the union of CV1 and CV2."
>
> Everything is understandble , but for
> CV2 T C2::*

It's a member pointer
T is the type of the member, and C2 is the class that contains a T.
Since C1 is derived from C2, it will contain the same member of type T.

Members can have a cv-qualifier seq too and CV2 is that cv-qualifier
seq.

So if you have a const int Base::m_i; then &Base::m_i is a CV2 T C2::*
with CV2=const, T=int and C2==Base.

HTH,
Michiel Salters