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Hi, I am new to linux and was writing a program that uses linux POSIX
Threads. I had to show some activity on the screen while some files
will be copied in the background. I thought of implementing it using
threads and to just test the algorithm I wrote the following,

#include <stdio.h>
#include <pthread.h>
#include <unistd.h>

int running=1;
char *signs[]={"|","/","-","\\"};
int cur_sign=0;

void* run(void* args){
while(running){
printf("%s",signs[cur_sign]);
fflush(stdin);
(cur_sign==3)? cur_sign=0 : cur_sign++;
sleep(1);
printf("\b");
}
return NULL;
}

int main(void){
pthread_t t;
pthread_create(&t,NULL,run,NULL);
sleep(10);
running=0;
return 0;
}

The problem with this is, it simply doesn't show the signs in the
repeating printf statements in run function, it waits for 10 secs and
then displays the last printf result and ends. While the same logic
works fine with Java threads, what is going on here? Another thing,
when I add a \n to the printf statement in the loop
[printf("%s\n",signs[cur_sign]);], it starts printing them in the right
way but in separate lines (that is expected), but what happens in the
first case?

"Sourav" <> wrote in message
news: ups.com...
> Hi, I am new to linux and was writing a program that uses linux POSIX
> Threads. I had to show some activity on the screen while some files
> will be copied in the background. I thought of implementing it using
> threads and to just test the algorithm I wrote the following,
>
> #include <stdio.h>
> #include <pthread.h>
> #include <unistd.h>
>
> int running=1;
> char *signs[]={"|","/","-","\\"};
> int cur_sign=0;
>
> void* run(void* args){
> while(running){
> printf("%s",signs[cur_sign]);
> fflush(stdin);

fflush( stdout);

> (cur_sign==3)? cur_sign=0 : cur_sign++;
> sleep(1);
> printf("\b");
> }
> return NULL;
> }
>
> int main(void){
> pthread_t t;
> pthread_create(&t,NULL,run,NULL);
> sleep(10);
> running=0;
> return 0;
> }
>
> The problem with this is, it simply doesn't show the signs in the
> repeating printf statements in run function, it waits for 10 secs and
> then displays the last printf result and ends. While the same logic
> works fine with Java threads, what is going on here? Another thing,
> when I add a \n to the printf statement in the loop
> [printf("%s\n",signs[cur_sign]);], it starts printing them in the right
> way but in separate lines (that is expected), but what happens in the
> first case?
>

Sourav wrote:
>
> Hi, I am new to linux and was writing a program that uses linux POSIX
> Threads. I had to show some activity on the screen while some files
> will be copied in the background. I thought of implementing it using
> threads and to just test the algorithm I wrote the following,

Threads are OT here, but perhaps your problem isn't really related to
threads.

[...]
> printf("%s",signs[cur_sign]);
> fflush(stdin);
[...]

Flushing input streams is undefined. Did you perhaps mean to flush
stdout, to force the output to be sent?

--
+-------------------------+--------------------+-----------------------+
| Kenneth J. Brody | www.hvcomputer.com | #include |
| kenbrody/at\spamcop.net | www.fptech.com | <std_disclaimer.h> |
+-------------------------+--------------------+-----------------------+
Don't e-mail me at: <private.php?do=newpm&u=>

Kenneth Brody wrote:
> Sourav wrote:
> >
> > Hi, I am new to linux and was writing a program that uses linux POSIX
> > Threads. I had to show some activity on the screen while some files
> > will be copied in the background. I thought of implementing it using
> > threads and to just test the algorithm I wrote the following,
>
> Threads are OT here, but perhaps your problem isn't really related to
> threads.
>
> [...]
> > printf("%s",signs[cur_sign]);
> > fflush(stdin);
> [...]
>
> Flushing input streams is undefined. Did you perhaps mean to flush
> stdout, to force the output to be sent?
>
> --


Yes, that was actually fflush(stdout), I typed it wrong here!
> +-------------------------+--------------------+-----------------------+
> | Kenneth J. Brody | www.hvcomputer.com | #include |
> | kenbrody/at\spamcop.net | www.fptech.com | <std_disclaimer.h> |
> +-------------------------+--------------------+-----------------------+
> Don't e-mail me at: <private.php?do=newpm&u=>

Try printf("\n") before printf("%s") it is posible tha the bash colon is
overwriting yor output to stdout

#include <stdio.h>
#include <pthread.h>
#include <unistd.h>
#include <stdlib.h>
int running=1;
char *signs[]={(char*)'|',(char*)'/',(char*)'-',(char*)'\\'};
int cur_sign=0;


void* run(void* args){
while(running){
printf("%c\r",(int)*(signs+cur_sign));
(cur_sign==3) ? cur_sign=0 : cur_sign++;
fflush(stdout);
sleep(1);
}
return NULL;
}

int main(void){
pthread_t t;
pthread_create(&t,NULL,run,NULL);
sleep(10);
running=0;
exit(0);
}

Gregorovic Peter <> wrote:

> #include <stdio.h>
> #include <pthread.h>
> #include <unistd.h>

(snip)

Please take these non-C headers and show them unto the gurus of
comp.unix.programmer, who will show unto thee forthwith their stores
of wisdom.

--
C. Benson Manica | I *should* know what I'm talking about - if I
cbmanica(at)gmail.com | don't, I need to know. Flames welcome.

Gregorovic Peter <> writes:
> Try printf("\n") before printf("%s") it is posible tha the bash colon
> is overwriting yor output to stdout

You're replying to an article that was posted several months ago.
Please provide context when you post a followup; see
<http://cfaj.freeshell.org/google/>.

The article in question was off-topic when it was posted, and it still
is.

--
Keith Thompson (The_Other_Keith) kst- <http://www.ghoti.net/~kst>
San Diego Supercomputer Center <*> <http://users.sdsc.edu/~kst>
We must do something. This is something. Therefore, we must do this.